Jump statement overview in C++ - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to exit the loop immediately when i equals 3.

C++

for (int i = 0; i < 5; i++) {
    if (i == 3) {
        [1];
    }
    std::cout << i << std::endl;
}

Drag options to blanks, or click blank then click option'

Abreak

Bcontinue

Creturn

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'continue' instead of 'break' will skip the rest of the loop but not exit it.

The break statement exits the loop immediately when the condition is met.

2fill in blank

medium

Complete the code to skip printing the number 2 inside the loop.

C++

for (int i = 0; i < 5; i++) {
    if (i == 2) {
        [1];
    }
    std::cout << i << std::endl;
}

Drag options to blanks, or click blank then click option'

Aexit

Bbreak

Creturn

Dcontinue

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' will stop the loop entirely, not just skip one iteration.

The continue statement skips the current loop iteration and moves to the next one.

3fill in blank

hard

Fix the error in the code to return from the function when x is negative.

C++

void checkNumber(int x) {
    if (x < 0) {
        [1];
    }
    std::cout << "Number is non-negative" << std::endl;
}

Drag options to blanks, or click blank then click option'

Areturn

Bcontinue

Cbreak

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' or 'continue' outside loops causes errors.

The return statement exits the function immediately.

4fill in blank

hard

Fill both blanks to create a loop that skips even numbers and stops when i reaches 7.

C++

for (int i = 0; i < 10; i++) {
    if (i [1] 2 [2] 0) {
        continue;
    }
    if (i == 7) {
        break;
    }
    std::cout << i << std::endl;
}

Drag options to blanks, or click blank then click option'

A%

B==

C!=

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong comparison operators or 'break' instead of 'continue'.

The condition i % 2 == 0 checks if i is even, and continue skips printing even numbers.

5fill in blank

hard

Fill all three blanks to create a function that returns the first positive number in an array or -1 if none found.

C++

int firstPositive(int arr[], int size) {
    for (int i = 0; i < size; i++) {
        if (arr[[1]] [2] 0) {
            [3] arr[i];
        }
    }
    return -1;
}

Drag options to blanks, or click blank then click option'

Ai

B>

Creturn

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong index or comparison, or forgetting to return the value.

We check each element with arr[i] > 0 and use return to exit the function immediately with the first positive number.

Practice

1. Which jump statement in C++ is used to immediately exit a loop or switch statement?

easy

A. break

B. continue

C. return

D. goto

Solution

1. Step 1: Understand the purpose of break

   The break statement immediately exits the nearest enclosing loop or switch.

2. Step 2: Compare with other jump statements

   continue skips to the next loop iteration, return exits a function, and goto jumps to a label.

3. Final Answer:

   break -> Option A

4. Quick Check:

   Exit loop early = break [OK]

Hint: Break stops loops/switch immediately [OK]

Common Mistakes:

• Confusing break with continue
• Thinking return exits loops only
• Using goto without label

2. Which of the following is the correct syntax to skip the current iteration in a loop in C++?

easy

A. skip;

B. break;

C. continue;

D. return;

Solution

1. Step 1: Identify the statement that skips current iteration

   The continue; statement skips the rest of the current loop iteration and moves to the next.

2. Step 2: Verify syntax correctness

   skip; is invalid, break; exits loop, return; exits function.

3. Final Answer:

   continue; -> Option C

4. Quick Check:

   Skip iteration = continue [OK]

Hint: Continue skips current loop iteration [OK]

Common Mistakes:

• Using break to skip iteration
• Using return inside loops incorrectly
• Writing skip instead of continue

3. What will be the output of the following C++ code?

int main() {
    for (int i = 1; i <= 5; i++) {
        if (i == 3) continue;
        std::cout << i << " ";
    }
    return 0;
}

medium

A. 1 2 4 5

B. 1 2

C. 1 2 3 4 5

D. 3 4 5

Solution

1. Step 1: Analyze the loop and condition

   The loop runs from 1 to 5. When i == 3, continue; skips printing 3.

2. Step 2: Determine printed values

   Values 1, 2, 4, and 5 are printed with spaces.

3. Final Answer:

   1 2 4 5 -> Option A

4. Quick Check:

   Skip 3 with continue = 1 2 4 5 [OK]

Hint: Continue skips printing 3, so output excludes 3 [OK]

Common Mistakes:

• Including 3 in output
• Confusing break with continue
• Not printing spaces correctly

4. Identify the error in this C++ code snippet:

int main() {
    for (int i = 0; i < 5; i++) {
        if (i == 2) break
        std::cout << i << " ";
    }
    return 0;
}

medium

A. Missing return statement

B. Incorrect loop condition

C. Using break inside loop is invalid

D. Missing semicolon after break statement

Solution

1. Step 1: Check syntax of break statement

   The break statement must end with a semicolon. Here it is missing.

2. Step 2: Confirm other parts are correct

   The loop condition and return statement are correct; break is valid inside loops.

3. Final Answer:

   Missing semicolon after break statement -> Option D

4. Quick Check:

   break needs semicolon [OK]

Hint: Always put semicolon after break [OK]

Common Mistakes:

• Omitting semicolon after break
• Thinking break can't be inside loops
• Confusing break with continue syntax

5. Consider this C++ function:

int findFirstEven(int arr[], int size) {
    for (int i = 0; i < size; i++) {
        if (arr[i] % 2 == 0) return arr[i];
    }
    return -1;
}

What does the return statement inside the loop do?

hard

A. Skips the current iteration and continues the loop

B. Exits the loop and returns the first even number found

C. Exits the function only after the loop finishes

D. Jumps to a labeled statement

Solution

1. Step 1: Understand return inside a loop

   The return inside the loop immediately exits the function when an even number is found.

2. Step 2: Confirm behavior after return

   No further iterations or code run after return; function ends and returns value.

3. Final Answer:

   Exits the loop and returns the first even number found -> Option B

4. Quick Check:

   Return exits function immediately [OK]

Hint: Return exits function immediately, not just loop [OK]

Common Mistakes:

• Thinking return skips iteration only
• Confusing return with break
• Assuming function continues after return