Computer Networks - Physical and Data Link Layer
If a Frequency Division Multiplexing system has channels at 100 MHz, 110 MHz, and 120 MHz, what is the minimum bandwidth needed assuming each channel requires 5 MHz?
If a Frequency Division Multiplexing system has channels at 100 MHz, 110 MHz, and 120 MHz, what is the minimum bandwidth needed assuming each channel requires 5 MHz?
medium📝 Analysis Q5 of 15
Step-by-Step Solution
Solution:
Step 1: Calculate the total bandwidth required
The channel centers span from 100 MHz to 120 MHz (20 MHz span). Each channel requires 5 MHz, so minimum bandwidth = center span + channel bandwidth = 20 MHz + 5 MHz = 25 MHz.Step 2: Confirm with spacing
Centers spaced 10 MHz apart for 3 channels: total BW = (3-1) x 10 MHz + 5 MHz = 25 MHz.Final Answer:
25 MHz -> Option AQuick Check:
Total BW = (n-1) x spacing + channel BW = 25 MHz [OK]
Quick Trick: Total BW = (max freq - min freq) + channel BW [OK]
Common Mistakes:
MISTAKES- Calculating only the center span (20 MHz)
- Summing only channel bandwidths (15 MHz)
- Overestimating with larger sum (30 MHz)
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