Computer Networks - IP Addressing
You need to assign IP addresses to 300 devices in a network. Considering IPv4 address structure, what is the minimum number of bits required for the host part to accommodate all devices?
You need to assign IP addresses to 300 devices in a network. Considering IPv4 address structure, what is the minimum number of bits required for the host part to accommodate all devices?
hard📝 Application Q8 of 15
Step-by-Step Solution
Solution:
Step 1: Calculate minimum hosts needed
300 devices require at least 300 unique addresses.Step 2: Find bits to cover 300 addresses
2^8 = 256 (too small), 2^9 = 512 (enough), so 9 bits are needed.Step 3: Account for network and broadcast addresses
Usually 2 addresses are reserved, so 9 bits still suffice.Final Answer:
9 bits -> Option BQuick Check:
Bits for hosts ≥ log2(300) = 9 bits [OK]
Quick Trick: Use powers of two to cover device count [OK]
Common Mistakes:
MISTAKES- Choosing 8 bits (256 < 300)
- Ignoring reserved addresses
- Confusing total bits with host bits
Master "IP Addressing" in Computer Networks
Want More Practice?
15+ quiz questions · All difficulty levels · Free
Free Signup - Practice All QuestionsMore Computer Networks Quizzes