IPv4 address structure in Computer Networks - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to show the number of bits in an IPv4 address.

Computer Networks

ipv4_bits = [1]

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A128

B64

C32

D16

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing IPv4 with IPv6 bit length.

Choosing 64 or 128 bits which are for other protocols.

An IPv4 address is made up of 32 bits, which are divided into four 8-bit sections called octets.

2fill in blank

medium

Complete the code to represent an IPv4 address as four decimal numbers separated by dots.

Computer Networks

ipv4_address = "[1].168.1.1"

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A192

B256

C300

D500

Attempts:

3 left

💡 Hint

Common Mistakes

Using numbers greater than 255 in an IPv4 address.

Confusing decimal and binary representations.

Each part of an IPv4 address is a decimal number between 0 and 255. 192 is a common starting number for private networks.

3fill in blank

hard

Fix the error in the code that tries to split an IPv4 address into its parts.

Computer Networks

parts = ipv4_address.[1](".")

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Ajoin

Bsplit

Creplace

Dappend

Attempts:

3 left

💡 Hint

Common Mistakes

Using join which combines strings instead of splitting.

Using replace which changes characters but does not split.

The split method breaks a string into parts based on a separator. Here, it splits the IPv4 address into its four parts using the dot.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each octet string to its integer value.

Computer Networks

octet_values = {octet: int([1]) for octet in ipv4_address.[2](".")}

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Aoctet

Bipv4_address

Csplit

Djoin

Attempts:

3 left

💡 Hint

Common Mistakes

Using join instead of split.

Trying to convert the whole address string instead of each octet.

The comprehension converts each octet string to an integer. The split method divides the address into octets, and int(octet) converts each to a number.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps each octet to True if it is greater than 127, otherwise False.

Computer Networks

octet_flags = {octet: int(octet) [1] 127 for octet in ipv4_address.[2]("[3]")}

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A>

Bsplit

C.

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' for the comparison.

Using wrong separator in split method.

This comprehension checks if each octet number is greater than 127. The split method divides the address by dots, and the comparison operator > tests the value.