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If a stop-and-wait protocol has a round-trip time of 100 ms and frame transmission time of 10 ms, what is the maximum throughput as a percentage of the link capacity?

medium📝 Analysis Q5 of 15
Computer Networks - Physical and Data Link Layer
If a stop-and-wait protocol has a round-trip time of 100 ms and frame transmission time of 10 ms, what is the maximum throughput as a percentage of the link capacity?
A50%
B10%
C90.9%
D9.09%
Step-by-Step Solution
Solution:

  1. Step 1: Calculate throughput formula for stop-and-wait

    Throughput = Frame time / (Frame time + RTT) = 10 / (10 + 100) ms

  2. Step 2: Compute throughput percentage

    Throughput = 10 / 110 = 0.0909 = 9.09%

  3. Final Answer:

    9.09% -> Option D

  4. Quick Check:

    Throughput = Frame time / (Frame time + RTT) [OK]
Quick Trick: Throughput = Frame time / (Frame time + RTT) [OK]
Common Mistakes:
MISTAKES
  • Ignoring RTT in calculation
  • Using wrong units
  • Confusing throughput with link speed

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