Consider a sliding window protocol with window size 4. If the sender has sent packets 1, 2, 3, and 4, but only packets 1 and 2 are acknowledged, which packets can the sender send next?

medium📝 Analysis Q13 of 15

Computer Networks - Physical and Data Link Layer

APackets 5 and 6

BPackets 3, 4, and 5

CPackets 5, 6, 7, and 8

DPackets 3, 4, 5, and 6

Step-by-Step Solution

Solution:

Step 1: Understand sliding window acknowledgments
Packets 1 and 2 are acknowledged, so the window slides forward by 2 packets.
Step 2: Calculate new window range
Window size is 4, so after acknowledging 1 and 2, sender can send packets 5 and 6 (next two packets).
Final Answer:
Packets 5 and 6 -> Option A
Quick Check:
Window slides by acknowledged packets = Packets 5 and 6 [OK]

Quick Trick: Window slides by acknowledged packets count [OK]

Common Mistakes:

MISTAKES

Trying to resend unacknowledged packets
Sending too many packets beyond window size
Not sliding window after acknowledgments

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More Computer Networks Quizzes

Consider a sliding window protocol with window size 4. If the sender has sent packets 1, 2, 3, and 4, but only packets 1 and 2 are acknowledged, which packets can the sender send next?

Step 1: Understand sliding window acknowledgments

Step 2: Calculate new window range

Final Answer:

Quick Check:

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