Parse trees and derivations in Compiler Design - Time & Space Complexity
When building parse trees or derivations, we want to know how the work grows as the input size increases.
We ask: How much more time does it take to build these trees when the input gets bigger?
Analyze the time complexity of the following parse tree construction process.
function buildParseTree(input):
if input is a single token:
return leaf node
else:
for each production rule:
if rule matches input prefix:
leftTree = buildParseTree(matched part)
rightTree = buildParseTree(remaining part)
return new tree node with leftTree and rightTree
This code recursively builds a parse tree by splitting the input according to grammar rules.
Look for repeated steps that take most time.
- Primary operation: Recursive calls to build subtrees for parts of the input.
- How many times: Potentially once for each substring of the input, depending on grammar.
As input length grows, the number of substrings to consider grows quickly.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 1,000 recursive calls |
| 100 | About 1 million recursive calls |
| 1000 | About 1 billion recursive calls |
Pattern observation: The work grows roughly with the cube of input size because many substrings are checked.
Time Complexity: O(n^3)
This means the time to build the parse tree grows roughly with the cube of the input length, so doubling input size can make it take about eight times longer.
[X] Wrong: "Building a parse tree takes time just proportional to input length because we only read tokens once."
[OK] Correct: The parser often tries many ways to split the input, so it revisits parts multiple times, making the work grow faster than input length.
Understanding how parse tree building scales helps you explain parsing efficiency and challenges clearly, a useful skill in compiler design discussions.
"What if we used memoization to save results of subproblems? How would the time complexity change?"
Practice
Solution
Step 1: Understand the role of parse trees
Parse trees visually show how a sentence is broken down into parts according to grammar rules.Step 2: Differentiate from other compiler components
Unlike tokens or machine instructions, parse trees focus on syntax structure, not code or memory.Final Answer:
The hierarchical structure of a sentence based on grammar rules -> Option DQuick Check:
Parse tree = hierarchical structure [OK]
- Confusing parse tree with tokens list
- Thinking parse tree shows machine code
- Mixing parse tree with memory layout
Solution
Step 1: Identify standard grammar notation
In grammar, derivations use the arrow symbol → to show how a symbol expands.Step 2: Check each option's correctness
S → aSbuses → correctly; others use assignment or incorrect symbols.Final Answer:
S → aSb-> Option AQuick Check:
Derivation uses → symbol [OK]
- Using assignment symbols instead of arrow
- Confusing programming assignment with grammar rules
- Using incorrect arrow symbols
S → aSb | abWhat is the leftmost derivation of the string
aabb?Solution
Step 1: Apply leftmost derivation rules
Start with S, replace leftmost S usingS → aSbto getaSb.Step 2: Apply rule again to inner S
Replace inner S withaSbagain to getaaSbb, then replace S withabto getaabb.Final Answer:
S → aSb → aaSbb → aabb -> Option AQuick Check:
Leftmost derivation = S → aSb → aaSbb → aabb [OK]
- Replacing rightmost non-terminal first
- Skipping intermediate derivation steps
- Confusing production rules
S → aSb | ab to produce aabb:S → aSb → ab → aabbSolution
Step 1: Analyze the derivation steps
The derivation replaces S withaSb, then immediately replaces S withabbut in the wrong position.Step 2: Check correctness of replacement order
The inner S should be replaced after expanding the outer S fully; here it skips a step causing incorrect string formation.Final Answer:
Incorrectly replaced inner S with ab too early -> Option CQuick Check:
Early replacement error = Incorrectly replaced inner S with ab too early [OK]
- Replacing non-terminals out of order
- Assuming all strings are derivable
- Ignoring grammar rules sequence
E → E + T | TT → T * F | FF → (E) | idWhich parse tree correctly represents the expression
id + id * id?Solution
Step 1: Understand operator precedence in grammar
Multiplication (*) has higher precedence than addition (+), so '*' groups tighter.Step 2: Build parse tree accordingly
The root is '+', left child is 'id', right child is '*', which has two 'id' children.Final Answer:
Parse tree where '+' is root, left child 'id', right child '*' with two 'id' leaves -> Option BQuick Check:
Operator precedence respected = Parse tree where '+' is root, left child 'id', right child '*' with two 'id' leaves [OK]
- Ignoring operator precedence
- Swapping '+' and '*' as root
- Misplacing leaves in parse tree
Ready to prove it?
Pass the test and this pattern moves unknown
