[Solved] What is the mistake in the following code snippet?int value;printf("Input a value: ");scanf("%d", value);printf("Value is %d", value); | C

C - Input and Output

What is the mistake in the following code snippet?

int value;
printf("Input a value: ");
scanf("%d", value);
printf("Value is %d", value);

AThe format specifier '%d' is incorrect for an integer variable.

BThe variable 'value' should be passed by address using &value in scanf.

CThe printf statement should use '%f' instead of '%d'.

DThe variable 'value' should be declared as a float.

Step-by-Step Solution

Solution:

Step 1: Analyze scanf usage
scanf requires the address of the variable to store the input value.
Step 2: Identify the error
The code passes 'value' instead of '&value', so scanf cannot store the input correctly.
Final Answer:
The variable 'value' should be passed by address using &value in scanf. -> Option B
Quick Check:
Check if & is used with variables in scanf [OK]

Quick Trick: Always use & with variables in scanf [OK]

Common Mistakes:

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