[Solved] Find the error in this C code snippet:int x = 10; int y = 3; int z = x / y.0; printf("%d", z); — Ans: Using a floating-point number in integer division | C

C - Operators and Expressions

Find the error in this C code snippet:

int x = 10;
int y = 3;
int z = x / y.0;
printf("%d", z);

AUsing a floating-point number in integer division

BIncorrect format specifier in printf

CMissing semicolon after variable declaration

DDivision by zero error

Step-by-Step Solution

Solution:

Step 1: Analyze the division expression
The expression x / y.0 uses y.0 which attempts a floating-point literal but causes invalid syntax, as x and y are integers.
Step 2: Understand the syntax error
Using y.0 causes a compilation error due to invalid syntax in the integer division context.
Final Answer:
Using a floating-point number in integer division -> Option A
Quick Check:
Integer division must use integers only [OK]

Quick Trick: Integer division needs integer operands only [OK]

Common Mistakes:

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