[Solved] Why does this code print unexpected output?int num = 7;printf("Number: %f", num); — Ans: Using %f to print an int causes undefined behavior | C

C - Input and Output

Why does this code print unexpected output?

int num = 7;
printf("Number: %f", num);

AMissing semicolon after printf

BVariable num is not initialized

CUsing %f to print an int causes undefined behavior

Dprintf cannot print integers

Step-by-Step Solution

Solution:

Step 1: Check format specifier and variable type mismatch
The code uses %f (float) to print an int variable, which is incorrect and causes undefined behavior.
Step 2: Understand consequences of mismatch
This mismatch can print garbage values or cause runtime errors because printf expects a float argument but receives an int.
Final Answer:
Using %f to print an int causes undefined behavior -> Option C
Quick Check:
Match format specifier to variable type exactly [OK]

Quick Trick: Always match % specifier to variable type in printf [OK]

Common Mistakes:

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Why does this code print unexpected output?