For and while loops in Blockchain / Solidity - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to loop through the numbers 1 to 5 and print each number.

Blockchain / Solidity

for i in range(1, [1]):
    print(i)

Drag options to blanks, or click blank then click option'

A6

B5

C4

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using 5 as the end number, which excludes 5 from the loop.

The range function stops before the end number, so to include 5, we use 6.

2fill in blank

medium

Complete the code to create a while loop that stops when the variable count reaches 3.

Blockchain / Solidity

count = 0
while count [1] 3:
    print(count)
    count += 1

Drag options to blanks, or click blank then click option'

A>

B<

C==

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' which causes an infinite loop or no loop at all.

The loop should continue while count is less than 3.

3fill in blank

hard

Fix the error in the for loop to correctly print each item in the list.

Blockchain / Solidity

items = ['block', 'chain', 'loop']
for [1] in items:
    print(item)

Drag options to blanks, or click blank then click option'

Aitem

Bi

Cblock

Dchain

Attempts:

3 left

💡 Hint

Common Mistakes

Using a different variable name than in the print statement.

The loop variable should be item to match the print statement.

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, but only for words longer than 4 letters.

Blockchain / Solidity

lengths = {word: [1] for word in words if len(word) [2] 4}

Drag options to blanks, or click blank then click option'

Alen(word)

B<

C>

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' which selects shorter words.

We want the length of each word as the value, and only words longer than 4 letters.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values only if the value is greater than 10.

Blockchain / Solidity

result = [1]: [2] for k, v in data.items() if v [3] 10}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using the key directly without uppercase.

Using '<' instead of '>' for filtering.

Keys are uppercase using k.upper(), values are v, and we filter values greater than 10.

Practice

1. Which statement best describes a for loop in blockchain programming?

easy

A. It repeats code while a condition is true.

B. It runs only once and then stops.

C. It repeats code a fixed number of times.

D. It stops the program immediately.

Solution

1. Step 1: Understand the for loop purpose

   A for loop is designed to repeat code a set number of times, often counting through a range or list.

2. Step 2: Compare with other loop types

   A while loop repeats while a condition is true, not a fixed count. The other options do not describe for loops correctly.

3. Final Answer:

   It repeats code a fixed number of times. -> Option C

4. Quick Check:

   for loop = fixed repeats [OK]

Hint: For loops count repeats; while loops check conditions [OK]

Common Mistakes:

• Confusing for loops with while loops
• Thinking for loops run only once
• Believing for loops stop the program

2. Which of the following is the correct syntax for a while loop in blockchain programming?

easy

A. while (condition) { // code }

B. while condition: // code

C. while condition { // code }

D. while (condition): // code

Solution

1. Step 1: Identify correct syntax style

   In blockchain programming languages like Solidity, the while loop uses parentheses for the condition and curly braces for the code block.

2. Step 2: Check each option

   while (condition) { // code } matches the correct syntax: while (condition) { // code }. Others miss parentheses or use incorrect punctuation.

3. Final Answer:

   while (condition) { // code } -> Option A

4. Quick Check:

   Correct while syntax uses parentheses and braces [OK]

Hint: Remember: while(condition) { code } uses parentheses and braces [OK]

Common Mistakes:

• Omitting parentheses around condition
• Using colon instead of braces
• Mixing syntax from other languages

3. What will be the output of this code snippet?

uint sum = 0;
for (uint i = 1; i <= 3; i++) {
  sum += i;
}
return sum;

medium

A. 6

B. 3

C. 0

D. Error

Solution

1. Step 1: Analyze the loop iterations

   The loop runs with i = 1, 2, 3. Each time, sum adds i: sum = 0+1, then 1+2, then 3+3.

2. Step 2: Calculate the final sum

   Sum after loop: 0+1=1, 1+2=3, 3+3=6.

3. Final Answer:

   6 -> Option A

4. Quick Check:

   1+2+3 = 6 [OK]

Hint: Add numbers from 1 to 3 to get sum quickly [OK]

Common Mistakes:

• Stopping loop early
• Adding wrong values
• Confusing sum initialization

4. Identify the error in this code snippet:

uint i = 0;
while (i < 3)
  i++;

medium

A. Condition should be i <= 3

B. Missing braces {} for while loop body

C. Variable i should start at 1

D. Incorrect increment operator

Solution

1. Step 1: Check loop body syntax

   The while loop lacks braces {}, so only the next statement is inside the loop.

2. Step 2: Understand impact of missing braces

   Without braces, the loop runs only the single statement i++;. This is valid but can cause confusion or errors if more statements are added.

3. Final Answer:

   Missing braces {} for while loop body -> Option B

4. Quick Check:

   Always use braces for clarity in loops [OK]

Hint: Use braces {} to clearly define loop body [OK]

Common Mistakes:

• Assuming multiple statements run without braces
• Changing variable start unnecessarily
• Altering loop condition wrongly

5. You want to create a loop that counts down from 5 to 1 and stores each number in an array. Which code snippet correctly uses a for loop to do this in blockchain programming?

A) for (uint i = 5; i > 0; i--) { arr.push(i); }
B) for (uint i = 1; i <= 5; i++) { arr.push(i); }
C) for (uint i = 5; i >= 1; i++) { arr.push(i); }
D) for (uint i = 5; i > 0; i++) { arr.push(i); }

hard

A. Infinite loop due to i++ with i > 0

B. Counts up from 1 to 5

C. Infinite loop due to i++ with i >= 1

D. Counts down from 5 to 1 correctly

Solution

1. Step 1: Analyze each loop's counting direction

   Counts down from 5 to 1 correctly counts down from 5 to 1 using i-- and condition i > 0. Counts up from 1 to 5 counts up. Options C and D increase i but have conditions that cause infinite loops.

2. Step 2: Confirm correct loop behavior

   Counts down from 5 to 1 correctly correctly pushes 5,4,3,2,1 into the array and stops when i reaches 0.

3. Final Answer:

   Counts down from 5 to 1 correctly -> Option D

4. Quick Check:

   Decrement i with i-- and condition i > 0 for countdown [OK]

Hint: Use i-- and i > 0 to count down safely [OK]

Common Mistakes:

• Using i++ when counting down
• Wrong loop condition causing infinite loops
• Confusing counting up vs down