[Solved] What is wrong with this code snippet?var="abcabc"echo ${var/abc} - Ans: Syntax is correct and will print 'abc' | Bash Scripting

Bash Scripting - String Operations

What is wrong with this code snippet?

var="abcabc"
echo ${var/abc}

ASyntax is correct and will print 'abc'

BReplacement string is missing after slash

CSyntax requires double slashes for replacement

DThe slash should be escaped

Step-by-Step Solution

Solution:

Step 1: Check syntax completeness
The expression ${var/abc} is valid and deletes the first match of 'abc'.
Step 2: Confirm behavior
Nothing wrong; 'abcabc' becomes 'abc' after deleting first 'abc'. For replacement, add new string.
Final Answer:
Syntax is correct and will print 'abc' -> Option A
Quick Check:
Syntax valid, deletes first match = A [OK]

Quick Trick: Without new string after slash, deletes first match [OK]

Common Mistakes:

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