[Solved] What is wrong with this Bash code snippet for slicing an array?arr=(x y z) echo ${arr:1:2} - Ans: It will output an empty string | Bash Scripting

Bash Scripting - Arrays

What is wrong with this Bash code snippet for slicing an array?

arr=(x y z)
echo ${arr:1:2}

AIt will output an empty string

BIt will output only one element instead of two

CIt will cause a syntax error because slicing is not allowed

DIt will output 'y z' correctly

Step-by-Step Solution

Solution:

Step 1: Check slicing syntax correctness
The code uses ${arr:1:2} without @. For arrays, @ is needed to slice multiple elements.
Step 2: Understand the effect of missing @
Without @, Bash uses the first element x as a scalar string and slices it from index 1 length 2. Since x has length 1, it outputs an empty string.
Final Answer:
It will output an empty string -> Option A
Quick Check:
Missing @ slices first elem as string -> empty [OK]

Quick Trick: Always use @ for array slicing, else string slicing happens [OK]

Common Mistakes:

MISTAKES

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What is wrong with this Bash code snippet for slicing an array?