[Solved] Given a Bash array nums=(1 2 3 4 5 6), how do you remove all even numbers using array filtering? - Ans: nums=($(for n in "${nums[@]}"; do (( n % 2 != 0 )) && echo $n; done)) | Bash Scripting

Bash Scripting - Arrays

Given a Bash array nums=(1 2 3 4 5 6), how do you remove all even numbers using array filtering?

Anums=($(for n in "${nums[@]}"; do (( n % 2 != 0 )) && echo $n; done))

Bunset nums[0] nums[2] nums[4]

Cnums=(${nums[@]/2/})

Dnums=(${nums[@]:0:3})

Step-by-Step Solution

Solution:

Step 1: Use a loop to filter elements
Loop through each element and check if it is odd.
Step 2: Rebuild array with only odd numbers
Use command substitution to collect odd numbers into new array.
Final Answer:
nums=($(for n in "${nums[@]}"; do (( n % 2 != 0 )) && echo $n; done)) -> Option A
Quick Check:
Filter array with loop and condition [OK]

Quick Trick: Use loop and condition to filter array elements [OK]

Common Mistakes:

MISTAKES

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Given a Bash array nums=(1 2 3 4 5 6), how do you remove all even numbers using array filtering?