[Solved] Find the bug in this recursive function:countdown() { if [[ $1 -lt 0 ]]; then echo "Done" else echo $1 countdown $1 - 1 fi } countdown 3 | Bash Scripting

Bash Scripting - Functions

Find the bug in this recursive function:

countdown() {
  if [[ $1 -lt 0 ]]; then
    echo "Done"
  else
    echo $1
    countdown $1 - 1
  fi
}
countdown 3

AFunction name countdown is invalid

BIncorrect argument syntax in recursive call; should use arithmetic expansion

CMissing local keyword for variables

DBase case condition should be $1 -le 0

Step-by-Step Solution

Solution:

Step 1: Check recursive call argument
The call countdown $1 - 1 passes two arguments: current $1 and string '- 1', not the decremented value.
Step 2: Correct argument passing
It should be countdown $(( $1 - 1 )) to pass the decremented number as a single argument.
Final Answer:
Incorrect argument syntax in recursive call; should use arithmetic expansion -> Option B
Quick Check:
Use $(( )) to decrement argument in recursion [OK]

Quick Trick: Use $(( )) to calculate recursive arguments [OK]

Common Mistakes:

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