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Bash Scriptingscripting~20 mins

Recursive functions in Bash Scripting - Practice Problems & Coding Challenges

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Challenge - 5 Problems
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Recursive Mastery
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💻 Command Output
intermediate
2:00remaining
Output of a simple recursive factorial function
What is the output of this Bash script when run?
Bash Scripting
#!/bin/bash
factorial() {
  if [ "$1" -le 1 ]; then
    echo 1
  else
    local prev=$(factorial $(( $1 - 1 )))
    echo $(( $1 * prev ))
  fi
}
factorial 5
A120
B24
CError: command not found
D1
Attempts:
2 left
💡 Hint
Think about how factorial is defined and how recursion multiplies numbers down to 1.
💻 Command Output
intermediate
2:00remaining
Output of recursive Fibonacci function
What does this Bash script print when executed?
Bash Scripting
#!/bin/bash
fib() {
  if [ "$1" -le 1 ]; then
    echo $1
  else
    local a=$(fib $(( $1 - 1 )))
    local b=$(fib $(( $1 - 2 )))
    echo $(( a + b ))
  fi
}
fib 6
AError: maximum recursion depth exceeded
B13
C5
D8
Attempts:
2 left
💡 Hint
Remember the Fibonacci sequence starts 0,1,1,2,3,5,8...
📝 Syntax
advanced
2:00remaining
Identify the syntax error in this recursive function
Which option correctly identifies the syntax error in this Bash recursive function?
Bash Scripting
#!/bin/bash
countdown() {
  if [ $1 -le 0 ]
    echo "Done!"
  else
    echo "$1"
    countdown $(( $1 - 1 ))
  fi
}
countdown 3
AUsing echo inside recursion is not allowed
BIncorrect use of $(( )) for arithmetic
CMissing 'then' after the if condition
DMissing closing brace '}' for the function
Attempts:
2 left
💡 Hint
Check the if statement syntax carefully.
🚀 Application
advanced
2:00remaining
What is the output of this recursive directory listing script?
Given this Bash script that recursively lists files, what will it output when run in a directory with files 'a.txt' and subdirectory 'sub' containing 'b.txt'?
Bash Scripting
#!/bin/bash
list_files() {
  for item in "$1"/*; do
    if [ -d "$item" ]; then
      list_files "$item"
    else
      echo "$item"
    fi
  done
}
list_files "."
A
./a.txt
./sub/b.txt
B
a.txt
b.txt
C
./sub
./a.txt
./sub/b.txt
DError: infinite recursion
Attempts:
2 left
💡 Hint
The script prints file paths, not directories.
🔧 Debug
expert
2:00remaining
Why does this recursive function cause a stack overflow?
Examine this Bash recursive function. Why does it cause a stack overflow when called with 3?
Bash Scripting
#!/bin/bash
infinite() {
  echo "$1"
  infinite $1
}
infinite 3
AThe arithmetic expansion is missing in the recursive call
BThe function calls itself with the same argument, causing infinite recursion
CBash does not support recursion
DThe function lacks a base case to stop recursion
Attempts:
2 left
💡 Hint
Think about what stops recursion normally.

Practice

(1/5)
1. What is the main purpose of a base case in a recursive Bash function?
easy
A. To increase the input value for the next call
B. To call the function again with the same input
C. To print the current value of a variable
D. To stop the recursion and prevent infinite loops

Solution

  1. Step 1: Understand recursion basics

    A recursive function calls itself repeatedly with smaller inputs.
  2. Step 2: Role of base case

    The base case stops the recursion to avoid infinite loops and eventual crash.
  3. Final Answer:

    To stop the recursion and prevent infinite loops -> Option D
  4. Quick Check:

    Base case = stop recursion [OK]
Hint: Base case always stops recursion to avoid endless calls [OK]
Common Mistakes:
  • Forgetting the base case causes infinite recursion
  • Using base case to increase input instead of stopping
  • Confusing base case with recursive step
2. Which of the following is the correct syntax to define a recursive function named countdown in Bash?
easy
A. countdown() { while [ $1 -gt 0 ]; do echo $1; (( $1-- )); done; echo Done; }
B. def countdown(n): if n <= 0: print('Done') else: print(n) countdown(n-1)
C. function countdown() { if [[ $1 -le 0 ]]; then echo Done; else echo $1; countdown $(( $1 - 1 )); fi }
D. function countdown { echo $1; countdown $(( $1 - 1 )); }

Solution

  1. Step 1: Identify Bash function syntax

    Bash functions use the syntax: function name() { commands; } or name() { commands; }.
  2. Step 2: Check recursive call and base case

    function countdown() { if [[ $1 -le 0 ]]; then echo Done; else echo $1; countdown $(( $1 - 1 )); fi } correctly defines a function with a base case (if $1 <= 0) and recursive call countdown $(( $1 - 1 )).
  3. Final Answer:

    function countdown() { if [[ $1 -le 0 ]]; then echo Done; else echo $1; countdown $(( $1 - 1 )); fi } -> Option C
  4. Quick Check:

    Bash recursion syntax = function countdown() { if [[ $1 -le 0 ]]; then echo Done; else echo $1; countdown $(( $1 - 1 )); fi } [OK]
Hint: Look for Bash syntax with base case and recursive call [OK]
Common Mistakes:
  • Using Python syntax in Bash function
  • Missing base case causing infinite recursion
  • Incorrect function declaration without parentheses
3. What will be the output of this Bash script?
factorial() {
  if [[ $1 -le 1 ]]; then
    echo 1
  else
    local prev=$(factorial $(( $1 - 1 )))
    echo $(( $1 * prev ))
  fi
}
factorial 3
medium
A. 1
B. 6
C. 3
D. 9

Solution

  1. Step 1: Understand factorial recursion

    factorial(3) calls factorial(2), which calls factorial(1). factorial(1) returns 1.
  2. Step 2: Calculate factorial values

    factorial(2) = 2 * 1 = 2; factorial(3) = 3 * 2 = 6.
  3. Final Answer:

    6 -> Option B
  4. Quick Check:

    3! = 6 [OK]
Hint: Factorial n = n * factorial(n-1), factorial(1) = 1 [OK]
Common Mistakes:
  • Confusing multiplication order
  • Forgetting base case returns 1
  • Assuming output is input value
4. Identify the error in this recursive Bash function that calculates the sum of numbers from 1 to n:
sum() {
  if [[ $1 -eq 0 ]]; then
    echo 0
  else
    echo $(( $1 + sum $(( $1 - 1 )) ))
  fi
}
sum 3
medium
A. Using echo inside arithmetic expression causes error
B. Missing base case for $1 == 1
C. Function name 'sum' is a reserved keyword
D. Incorrect decrement syntax $(( $1 - 1 ))

Solution

  1. Step 1: Analyze recursive call inside arithmetic

    The function calls sum recursively inside $(( ... )), but sum outputs text via echo, not a number directly.
  2. Step 2: Understand Bash arithmetic limitations

    Bash arithmetic expects numbers, but echo outputs string with newline, causing error.
  3. Final Answer:

    Using echo inside arithmetic expression causes error -> Option A
  4. Quick Check:

    Echo inside $(( )) = error [OK]
Hint: Avoid echo inside $(( )); use command substitution instead [OK]
Common Mistakes:
  • Assuming echo returns a number usable in arithmetic
  • Ignoring base case correctness
  • Thinking function name 'sum' is reserved
5. You want to write a recursive Bash function list_files that prints all files in a directory and its subdirectories. Which approach correctly handles recursion and avoids infinite loops?
hard
A. Check if the argument is a directory; if yes, list files and call list_files on each subdirectory; else print the file name
B. Call list_files on the directory without checking type, then print the directory name
C. Use a loop to list files only in the current directory without recursion
D. Call list_files on all files and directories without base case

Solution

  1. Step 1: Understand recursive directory traversal

    To list files recursively, check if the argument is a directory; if so, process contents recursively.
  2. Step 2: Avoid infinite loops by checking file type

    Only recurse into directories; print file names directly to avoid infinite recursion.
  3. Final Answer:

    Check if the argument is a directory; if yes, list files and call list_files on each subdirectory; else print the file name -> Option A
  4. Quick Check:

    Directory check + recursive call = correct recursion [OK]
Hint: Always check if input is directory before recursive call [OK]
Common Mistakes:
  • Recursing without checking if input is directory
  • Missing base case causing infinite recursion
  • Not printing files when input is a file
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