[Solved] What will be the output of this command?grep -v "error" log.txtAssuming log.txt contains:error: file not foundsuccess: file savederror: access denied | Bash Scripting

Bash Scripting - Text Processing in Scripts

What will be the output of this command?

grep -v "error" log.txt

Assuming log.txt contains:
error: file not found
success: file saved
error: access denied

Aerror: file not found success: file saved error: access denied

Bsuccess: file saved

Cerror: access denied

DNo output

Step-by-Step Solution

Solution:

Step 1: Understand -v option
The -v option inverts the match, so grep prints lines NOT containing "error".
Step 2: Check lines in log.txt
Only "success: file saved" does not contain "error", so only this line is printed.
Final Answer:
success: file saved -> Option B
Quick Check:
-v inverts grep matches [OK]

Quick Trick: Use -v to show lines without the pattern [OK]

Common Mistakes:

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