String variables in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to assign the text "Hello" to a variable named greeting.

Bash Scripting

greeting=[1]

Drag options to blanks, or click blank then click option'

Agreeting

B"Hello"

CHello

D'Hello'

Attempts:

3 left

💡 Hint

Common Mistakes

Assigning the string without quotes causes errors or unexpected behavior.

Using single quotes when double quotes are expected for variable expansion.

In bash, to assign a string with spaces or special characters, you must enclose it in quotes. Double quotes allow variable expansion if needed.

2fill in blank

medium

Complete the code to print the value of the variable name.

Bash Scripting

echo [1]

Drag options to blanks, or click blank then click option'

A$name

Bname

C"name"

D'name'

Attempts:

3 left

💡 Hint

Common Mistakes

Printing the variable name as a string instead of its value.

Forgetting the $ sign before the variable.

To print the value of a variable in bash, prefix it with a dollar sign ($).

3fill in blank

hard

Fix the error in the code to correctly assign the string "World" to the variable word.

Bash Scripting

word=[1]

Drag options to blanks, or click blank then click option'

A"World"

BWorld

C'World

DWorld"

Attempts:

3 left

💡 Hint

Common Mistakes

Missing quotes or mismatched quotes cause syntax errors.

Using only one quote at start or end.

Strings must be enclosed in matching quotes. Option A uses proper double quotes.

4fill in blank

hard

Fill both blanks to assign "Hello" to greeting and then print it.

Bash Scripting

greeting=[1]
echo [2]

Drag options to blanks, or click blank then click option'

A"Hello"

Bgreeting

C$greeting

DHello

Attempts:

3 left

💡 Hint

Common Mistakes

Printing the variable name without $.

Assigning string without quotes.

Assign the string with quotes, then print the variable value with $.

5fill in blank

hard

Fill all four blanks to assign "User" to user, assign "Name" to name, then print both variables separated by a space.

Bash Scripting

user=[1]
name=[2]
echo [3] [4]

Drag options to blanks, or click blank then click option'

A"User"

B"Name"

C$user

D$name

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting quotes in assignments.

Printing variable names without $.

Not separating variables with space in echo.

Assign strings with quotes, then print variables with $ prefix separated by space.