String variables in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to assign the text "Hello" to a variable named greeting.

Bash Scripting

greeting=[1]

Drag options to blanks, or click blank then click option'

Agreeting

B"Hello"

CHello

D'Hello'

Attempts:

3 left

💡 Hint

Common Mistakes

Assigning the string without quotes causes errors or unexpected behavior.

Using single quotes when double quotes are expected for variable expansion.

In bash, to assign a string with spaces or special characters, you must enclose it in quotes. Double quotes allow variable expansion if needed.

2fill in blank

medium

Complete the code to print the value of the variable name.

Bash Scripting

echo [1]

Drag options to blanks, or click blank then click option'

A$name

Bname

C"name"

D'name'

Attempts:

3 left

💡 Hint

Common Mistakes

Printing the variable name as a string instead of its value.

Forgetting the $ sign before the variable.

To print the value of a variable in bash, prefix it with a dollar sign ($).

3fill in blank

hard

Fix the error in the code to correctly assign the string "World" to the variable word.

Bash Scripting

word=[1]

Drag options to blanks, or click blank then click option'

A"World"

BWorld

C'World

DWorld"

Attempts:

3 left

💡 Hint

Common Mistakes

Missing quotes or mismatched quotes cause syntax errors.

Using only one quote at start or end.

Strings must be enclosed in matching quotes. Option A uses proper double quotes.

4fill in blank

hard

Fill both blanks to assign "Hello" to greeting and then print it.

Bash Scripting

greeting=[1]
echo [2]

Drag options to blanks, or click blank then click option'

A"Hello"

Bgreeting

C$greeting

DHello

Attempts:

3 left

💡 Hint

Common Mistakes

Printing the variable name without $.

Assigning string without quotes.

Assign the string with quotes, then print the variable value with $.

5fill in blank

hard

Fill all four blanks to assign "User" to user, assign "Name" to name, then print both variables separated by a space.

Bash Scripting

user=[1]
name=[2]
echo [3] [4]

Drag options to blanks, or click blank then click option'

A"User"

B"Name"

C$user

D$name

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting quotes in assignments.

Printing variable names without $.

Not separating variables with space in echo.

Assign strings with quotes, then print variables with $ prefix separated by space.

Practice

1. What is the correct way to assign the string Hello to a variable named greeting in bash?

easy

A. greeting="Hello"

B. greeting = "Hello"

C. greeting: "Hello"

D. greeting <- "Hello"

Solution

1. Step 1: Understand bash variable assignment syntax

   In bash, variable assignment must have no spaces around the equals sign.

2. Step 2: Check the options for correct syntax

   greeting="Hello" uses no spaces and quotes the string correctly. The other options have invalid syntax.

3. Final Answer:

   greeting="Hello" -> Option A

4. Quick Check:

   No spaces around = and quotes needed [OK]

Hint: No spaces around = and use quotes for strings [OK]

Common Mistakes:

• Adding spaces around = causes syntax errors
• Forgetting quotes around strings with spaces
• Using wrong assignment symbols like : or <-

2. Which of the following correctly prints the value of the variable name in bash?

easy

A. echo name

B. echo $name

C. echo &name

D. echo %name

Solution

1. Step 1: Recall how to access variable values in bash

   Use the dollar sign ($) before the variable name to get its value.

2. Step 2: Evaluate each option

   echo $name uses $name correctly. echo name prints the literal word 'name'. The other options use invalid symbols.

3. Final Answer:

   echo $name -> Option B

4. Quick Check:

   Use $ to access variable value [OK]

Hint: Use $ before variable to print its value [OK]

Common Mistakes:

• Forgetting $ prints variable name, not value
• Using wrong symbols like & or %
• Confusing variable access with assignment

3. What will be the output of this bash script?

name="Alice"
echo "Hello, $name!"

medium

A. Hello, Alice!

B. Hello, $name!

C. Hello, name!

D. Hello, !

Solution

1. Step 1: Understand variable assignment and usage

   The variable name is assigned the string "Alice".

2. Step 2: Analyze the echo command with variable expansion

   The echo command uses double quotes, so $name is replaced by its value "Alice".

3. Final Answer:

   Hello, Alice! -> Option A

4. Quick Check:

   Variables expand inside double quotes [OK]

Hint: Variables expand inside double quotes, not single quotes [OK]

Common Mistakes:

• Expecting variable expansion inside single quotes
• Printing variable name literally without $
• Forgetting to assign variable before use

4. Identify the error in this bash script:

message = "Hi there"
echo $message

medium

A. Variable name is invalid

B. Quotes should be single quotes

C. Missing $ before variable in echo

D. Spaces around = cause syntax error

Solution

1. Step 1: Check variable assignment syntax

   In bash, no spaces are allowed around the equals sign when assigning variables.

2. Step 2: Analyze the given script

   The line message = "Hi there" has spaces around =, causing a syntax error.

3. Final Answer:

   Spaces around = cause syntax error -> Option D

4. Quick Check:

   No spaces around = in assignments [OK]

Hint: No spaces around = in variable assignment [OK]

Common Mistakes:

• Adding spaces around =
• Using wrong quotes type causes no error here
• Forgetting $ in echo prints variable name literally

5. You want to store a user's full name with spaces in a variable fullname and then print it. Which script correctly does this?

hard

A. fullname=John Doe
echo $fullname

B. fullname='John Doe'
echo fullname

C. fullname="John Doe"
echo $fullname

D. fullname=John_Doe
echo $fullname

Solution

1. Step 1: Assign string with spaces to variable

   Strings with spaces must be quoted to be assigned correctly in bash.

2. Step 2: Print the variable value

   Use echo $fullname to print the stored string value.

3. Final Answer:

   fullname="John Doe" echo $fullname -> Option C

4. Quick Check:

   Quote strings with spaces and use $ to print [OK]

Hint: Quote strings with spaces; use $ to print variable [OK]

Common Mistakes:

• Not quoting strings with spaces causes errors
• Printing variable name without $ prints literal text
• Using underscores instead of spaces changes the string