String variables in Bash Scripting - Practice Problems & Coding Challenges

Challenge - 5 Problems

💻 Command Output

intermediate

What is the output of this Bash script?

Consider the following Bash script that manipulates string variables. What will it print?

Bash Scripting

name="Alice"
welcome="Hello, $name!"
echo "$welcome"

A Hello, !

B Hello, $name!

C Hello, Alice!

D name

💡 Hint

Remember how Bash replaces variables inside double quotes.

In Bash, variables inside double quotes are expanded to their values. So $name becomes Alice inside the string.

💻 Command Output

intermediate

What does this Bash script output when using single quotes?

Look at this script and decide what it prints:

Bash Scripting

name='Bob'
welcome='Hello, $name!'
echo "$welcome"

A Hello, !

B Hello, $name!

C Hello, Bob!

D name

💡 Hint

Single quotes prevent variable expansion in Bash.

Single quotes treat everything literally, so $name is not replaced by its value.

📝 Syntax

advanced

Which option correctly concatenates two strings in Bash?

You want to join two string variables, first="Good" and second="Morning". Which command correctly concatenates them into greeting?

Bash Scripting

first="Good"
second="Morning"

A greeting="$first$second"

B greeting=$first + $second

C greeting=$first.$second

D greeting="$first + $second"

💡 Hint

In Bash, string concatenation is done by placing variables side by side inside quotes.

Option A joins the two variables without spaces or operators, producing 'GoodMorning'.

🔧 Debug

advanced

Why does this Bash script produce an error?

This script tries to assign a string with spaces to a variable but fails. Identify the cause.

Bash Scripting

greeting=Hello World
echo "$greeting"

A Because the variable is read-only

B Because the variable name is invalid

C Because echo cannot print variables

D Because the string with spaces is not quoted

💡 Hint

Think about how Bash treats spaces in assignments.

Without quotes, Bash treats 'Hello' and 'World' as separate commands or arguments, causing an error.

🚀 Application

expert

What is the value of 'result' after running this script?

Given the script below, what is the value of the variable 'result'?

Bash Scripting

text="  Bash scripting  "
trimmed="${text##*( )}"
result="${trimmed%%*( )}"
echo "$result"

A Bash scripting

B gnitpircs hsaB

C scripting

D ash scripting

💡 Hint

Look up how parameter expansion with ## and %% works for trimming spaces.

The script uses Bash parameter expansion to trim leading and trailing spaces from the string.