How would you write a bash condition to check if a variable status is NOT equal to "success" AND a file output.log exists, using logical operators inside [ ]?

hard🚀 Application Q9 of 15

Bash Scripting - Conditionals

How would you write a bash condition to check if a variable status is NOT equal to "success" AND a file output.log exists, using logical operators inside [ ]?

A[ "$status" != "success" -a -e output.log ]

B[ ! "$status" = "success" -o -e output.log ]

C[ "$status" != "success" -o ! -e output.log ]

D[ ! "$status" = "success" -a ! -e output.log ]

Step-by-Step Solution

Solution:

Step 1: Check variable inequality syntax
Use "$status" != "success" to check NOT equal.
Step 2: Combine with file existence using AND
Use -a for AND inside [ ]. So condition is [ "$status" != "success" -a -e output.log ].
Final Answer:
[ "$status" != "success" -a -e output.log ] -> Option A
Quick Check:
Use != for not equal and -a for AND [OK]

Quick Trick: Use != for not equal and -a for AND inside [ ] [OK]

Common Mistakes:

MISTAKES

Using ! with = incorrectly
Mixing -o and -a wrongly
Forgetting quotes around variables

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How would you write a bash condition to check if a variable status is NOT equal to "success" AND a file output.log exists, using logical operators inside [ ]?

Step 1: Check variable inequality syntax

Step 2: Combine with file existence using AND

Final Answer:

Quick Check:

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