Bash Scripting - Variables
What will be the output of this script?
var="5"
echo "$var2"
echo "${var}2"What will be the output of this script?
medium📝 Command Output Q5 of 15
Step-by-Step Solution
Solution:
Step 1: Analyze first echo "$var2"
Variable var2 is undefined, so it prints empty line.Step 2: Analyze second echo "${var}2"
Braces separate var from 2, so it prints 5 followed by 2, resulting in 52.Final Answer:
(empty line) 52 -> Option AQuick Check:
Undefined var empty, braces separate = A [OK]
Quick Trick: Use braces to avoid variable name confusion [OK]
Common Mistakes:
MISTAKES- Expecting $var2 to print 5
- Not using braces to separate variable and text
- Assuming undefined variables print error
Master "Variables" in Bash Scripting
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