[Solved] How would you write a C-style for loop in bash to print even numbers from 2 to 10 inclusive? - Ans: for ((i=2; i<=10; i+=2)); do echo $i; done | Bash Scripting

Bash Scripting - Loops

How would you write a C-style for loop in bash to print even numbers from 2 to 10 inclusive?

Afor ((i=0; i<=10; i+=2)); do echo $i; done

Bfor ((i=1; i<10; i++)); do if (( i % 2 == 0 )); then echo $i; fi; done

Cfor ((i=2; i<10; i+=2)); do echo $i; done

Dfor ((i=2; i<=10; i+=2)); do echo $i; done

Step-by-Step Solution

Solution:

Step 1: Identify loop start, end, and step
Start at 2, end at 10 inclusive, step by 2 to get even numbers.
Step 2: Check options for correct range and increment
for ((i=2; i<=10; i+=2)); do echo $i; done matches start=2, end=10, increment=2 correctly.
Final Answer:
for ((i=2; i<=10; i+=2)); do echo $i; done -> Option D
Quick Check:
Even numbers loop = for ((i=2; i<=10; i+=2)); do echo $i; done [OK]

Quick Trick: Use i+=2 to step through even numbers [OK]

Common Mistakes:

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How would you write a C-style for loop in bash to print even numbers from 2 to 10 inclusive?