C-style for loop in Bash Scripting - Mini Project: Build & Apply

Using C-style for loop in Bash scripting

📖 Scenario: You are managing a small inventory system using a Bash script. You want to count from 1 to 5 to simulate checking five items in stock.

🎯 Goal: Build a Bash script that uses a C-style for loop to count from 1 to 5 and print each number.

📋 What You'll Learn

Create a variable called start and set it to 1

Create a variable called end and set it to 5

Use a C-style for loop with i starting from start to end

Print the value of i inside the loop

💡 Why This Matters

🌍 Real World

Counting or iterating a fixed number of times is common in automation scripts, like processing files or checking system status.

💼 Career

Knowing how to write loops in Bash helps in system administration, DevOps, and automation roles where scripts manage repetitive tasks.

1

Set up start and end variables

Create a variable called start and set it to 1. Create another variable called end and set it to 5.

Bash Scripting

# Your code here

Need a hint?

Use start=1 and end=5 to create the variables.

2

Write the C-style for loop

Write a C-style for loop using i starting from start to end. Use the syntax for (( i=start; i<=end; i++ )).

Bash Scripting

start=1
end=5
# Your code here

Need a hint?

Use for (( i=start; i<=end; i++ )) and echo $i inside the loop.

3

Add the loop body to print numbers

Inside the for loop, write echo $i to print the current value of i.

Bash Scripting

start=1
end=5
for (( i=start; i<=end; i++ ))
do
    # Your code here
done

Need a hint?

Use echo $i to print the number inside the loop.

4

Run the script and display output

Run the script and print the numbers from 1 to 5, each on its own line.

Bash Scripting

start=1
end=5
for (( i=start; i<=end; i++ ))
do
    echo $i
done
# Run the script to see output

Need a hint?

Run the script using bash script.sh or execute it directly.