[Solved] Why does the following C-style for loop in bash print nothing?for ((i=5; i - Ans: Because the loop condition i<5 is false at start, so loop never runs | Bash Scripting

Bash Scripting - Loops

Why does the following C-style for loop in bash print nothing?

for ((i=5; i<5; i++)); do echo $i; done

ABecause increment operator is incorrect

BBecause the loop condition i<5 is false at start, so loop never runs

CBecause echo command is missing

DBecause variable i is not initialized

Step-by-Step Solution

Solution:

Step 1: Check loop initialization and condition
Loop starts with i=5, condition is i<5, which is false immediately.
Step 2: Understand loop execution
Since condition is false at start, loop body never executes, so nothing prints.
Final Answer:
Because the loop condition i<5 is false at start, so loop never runs -> Option B
Quick Check:
Loop runs only if condition true initially [OK]

Quick Trick: Loop runs only if condition true at start [OK]

Common Mistakes:

MISTAKES

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