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When is Approach 2 more efficient than Approach 1?

hard⚖️ Approach Comparison Q8 of Q15
Tree: Depth-First Search - Count Complete Tree Nodes
Consider two approaches to count nodes in a complete binary tree: Approach 1: Simple DFS traversal counting all nodes. Approach 2: Using tree height to detect perfect subtrees and count nodes recursively. When is Approach 2 more efficient than Approach 1?
AWhen the tree is complete and balanced, allowing height checks to prune traversal.
BWhen the tree is empty or has only one node.
CWhen the tree is skewed and has height close to n.
DWhen the tree is a general binary tree with arbitrary missing nodes.
Step-by-Step Solution
Solution:
  1. Step 1: Analyze Approach 2 efficiency

    Approach 2 leverages completeness and balanced structure to prune traversal.
  2. Step 2: Identify when pruning helps

    In complete and balanced trees, height checks allow skipping large subtrees.
  3. Final Answer:

    Option A -> Option A
  4. Quick Check:

    Approach 2 is more efficient on balanced complete trees due to pruning [OK]
Quick Trick: Height-based pruning helps most on balanced complete trees [OK]
Common Mistakes:
MISTAKES
  • Assuming Approach 2 always better
  • Ignoring edge cases like skewed trees
Trap Explanation:
PITFALL
  • Candidates often overlook that Approach 2's advantage is minimal on skewed or general trees.
Interviewer Note:
CONTEXT
  • Tests understanding of trade-offs between traversal and pruning.
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