[Solved] Which of the following problems CANNOT be solved using the House Robber III (On Tree) pattern? - Ans: Find maximum path sum in a binary tree where path can start and end anywhere | Tree: Depth-First Search

Tree: Depth-First Search - House Robber III (On Tree)

Which of the following problems CANNOT be solved using the House Robber III (On Tree) pattern?

AMaximize sum of non-adjacent nodes in a binary tree

BCalculate maximum sum of nodes where no two directly connected nodes are chosen

CFind maximum path sum in a binary tree where path can start and end anywhere

DRob houses arranged in a binary tree without robbing adjacent nodes

Step-by-Step Solution

Solution:

Step 1: Analyze problem constraints
Options A, C, and D describe the same problem: no two adjacent nodes can be robbed, solvable by House Robber III pattern.
Step 2: Identify the odd one out
Finding maximum path sum in a binary tree where path can start and end anywhere allows adjacent nodes and different path shapes, requiring a different pattern (max path sum).
Final Answer:
Option C -> Option C
Quick Check:
Max path sum problem allows adjacent nodes, unlike House Robber III [OK]

Quick Trick: Max path sum allows adjacent nodes, unlike House Robber III [OK]

Common Mistakes:

MISTAKES

Trap Explanation:

PITFALL

Candidates often think all max-sum tree problems fit House Robber III, ignoring adjacency constraints.

Interviewer Note:

CONTEXT

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Which of the following problems CANNOT be solved using the House Robber III (On Tree) pattern?