Operating Systems - Process State Machine - Five-State Model
Why is it generally inefficient to keep a process in the Ready state for a long time without scheduling it to Running, especially in a multi-core system?
Why is it generally inefficient to keep a process in the Ready state for a long time without scheduling it to Running, especially in a multi-core system?
medium🪤 Complexity Trap Q13 of Q15
Step-by-Step Solution
Step 1: Understand Ready state resource usage
Processes in Ready state do not consume CPU cycles but occupy scheduling queues.Step 2: Analyze each option
A: Correct. Long Ready times cause loss of CPU cache locality and increase context switch overhead when finally scheduled.
B: Incorrect. Processes do not hold exclusive I/O or memory resources just by being Ready.
C: Incorrect. Ready processes do not consume CPU cycles.
D: Incorrect. Ready processes do not cause deadlocks by not performing I/O.Final Answer:
Option A -> Option AQuick Check:
Ready state delays hurt cache locality and increase context switch costs [OK]
Quick Trick: Ready state processes wait without CPU but lose cache locality and increase context switch overhead [OK]
Common Mistakes:
MISTAKES- Believing Ready processes consume CPU cycles
- Assuming Ready processes hold exclusive resources
- Confusing Ready state with Waiting state regarding I/O
Trap Explanation:
PITFALL- Option A is tempting because candidates may think Ready means active CPU use. Option B confuses resource holding with Running or Waiting states. Option D incorrectly links Ready state to deadlocks.
Interviewer Note:
CONTEXT- Tests understanding of performance trade-offs and misconceptions about process states in scheduling.
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