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What is the time complexity of the optimal min-heap approach for the Meeting Rooms II problem given n intervals?

medium🪤 Complexity Trap Q5 of Q15
Intervals - Meeting Rooms II (Minimum Conference Rooms)
What is the time complexity of the optimal min-heap approach for the Meeting Rooms II problem given n intervals?
AO(n²)
BO(n log n)
CO(n)
DO(n log k), where k is the number of rooms
Step-by-Step Solution
Solution:
  1. Step 1: Analyze sorting step

    Sorting intervals by start time takes O(n log n).
  2. Step 2: Analyze heap operations

    Each interval is pushed and popped at most once; heap operations cost O(log n) each, total O(n log n).
  3. Final Answer:

    Option B -> Option B
  4. Quick Check:

    Sorting dominates; heap operations add log n factor [OK]
Quick Trick: Sorting + heap operations -> O(n log n) [OK]
Common Mistakes:
MISTAKES
  • Assuming O(n²) due to nested loops
  • Ignoring sorting cost
Trap Explanation:
PITFALL
  • Candidates confuse brute force O(n²) with optimal heap approach.
Interviewer Note:
CONTEXT
  • Tests understanding of time complexity in interval scheduling.
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