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What is the time complexity of the optimal sweep line algorithm for Employee Free Time given N total intervals across all employees?

medium🪤 Complexity Trap Q5 of Q15
Intervals - Employee Free Time
What is the time complexity of the optimal sweep line algorithm for Employee Free Time given N total intervals across all employees?
AO(N²) due to nested interval comparisons
BO(N log N) due to sorting all interval endpoints
CO(N) because each interval is processed once
DO(N log W) where W is the timeline length
Step-by-Step Solution
Solution:
  1. Step 1: Count total events as 2N (start and end for each interval)

    Each interval contributes two endpoints, so total events = 2N.
  2. Step 2: Sorting these 2N events dominates complexity at O(N log N)

    Sorting 2N events is O(N log N). The sweep line then processes events in O(N) time.
  3. Final Answer:

    Option B -> Option B
  4. Quick Check:

    Sorting endpoints is the bottleneck, so O(N log N) [OK]
Quick Trick: Sorting endpoints dominates time complexity [OK]
Common Mistakes:
MISTAKES
  • Confusing N with timeline length or quadratic complexity
Trap Explanation:
PITFALL
  • Candidates often think nested loops cause O(N²), but sorting dominates.
Interviewer Note:
CONTEXT
  • Tests understanding of time complexity in sweep line algorithms.
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