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Using the line sweep algorithm, what is the output for intervals [[3,3]] and points [3,4]?

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Intervals - Count of Intervals Containing Each Point
Using the line sweep algorithm, what is the output for intervals [[3,3]] and points [3,4]?
A[1, 0]
B[0, 0]
C[0, 1]
D[1, 1]
Step-by-Step Solution
Solution:
  1. Step 1: Sort events

    Events: (3,+1), (3,0), (3+1=4,-1), (4,0). Sorted by coordinate and type: (3,+1), (3,0), (4,0), (4,-1).
  2. Step 2: Process events and count active intervals

    At coordinate 3: active increments to 1, point at 3 sees active=1. At coordinate 4: point at 4 sees active=1 before decrementing active to 0.
  3. Final Answer:

    Option D -> Option D
  4. Quick Check:

    Point at interval end+1 still counts active intervals before decrement [OK]
Quick Trick: Events at same coordinate: start (+1) before point (0) before end (-1) [OK]
Common Mistakes:
MISTAKES
  • Assuming point at end+1 is outside interval coverage
  • Misordering events causing wrong active count
  • Ignoring points at interval boundaries
Trap Explanation:
PITFALL
  • Candidates often think points at end+1 are outside coverage, but event order matters.
Interviewer Note:
CONTEXT
  • Tests handling of edge cases with zero-length intervals and event ordering.
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