[Solved] Suppose meetings can be attended multiple times if they do not overlap, and you want to find the maximum... Which approach fundamentally changes compared to the original Meeting Rooms I problem? | Intervals

Intervals - Meeting Rooms I

Suppose meetings can be attended multiple times if they do not overlap, and you want to find the maximum number of meetings a person can attend (including repeats). Which approach fundamentally changes compared to the original Meeting Rooms I problem?

AUse the same sorting and overlap check approach as Meeting Rooms I

BSort intervals by end time and greedily select non-overlapping meetings

CUse interval scheduling with dynamic programming to count maximum attendable meetings

DApply brute force checking all pairs repeatedly

Step-by-Step Solution

Solution:

Step 1: Understand problem variant
Allowing multiple attendance and maximizing count requires selecting intervals, not just overlap detection.
Step 2: Apply greedy interval scheduling
Sorting by end time and greedily selecting earliest finishing meetings maximizes count.
Step 3: Contrast with Meeting Rooms I
Original problem only checks feasibility; this requires optimization approach.
Final Answer:
Option B -> Option B
Quick Check:
Greedy by end time solves maximum meeting attendance [OK]

Quick Trick: Max meetings -> sort by end time, greedy select [OK]

Common Mistakes:

MISTAKES

Using overlap check only
Confusing start time sorting with end time sorting

Trap Explanation:

PITFALL

Candidates often try to reuse Meeting Rooms I approach without adapting to optimization variant.

Interviewer Note:

CONTEXT

Tests ability to adapt approach for problem variants.

Master "Meeting Rooms I" in Intervals

3 interactive learning modes - each teaches the same concept differently

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Which approach fundamentally changes compared to the original Meeting Rooms I problem?

Step 1: Understand problem variant

Step 2: Apply greedy interval scheduling

Step 3: Contrast with Meeting Rooms I

Final Answer:

Quick Check:

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