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What is the time complexity of the optimal greedy algorithm using a stack to remove k digits from a number string of length n to get the smallest number?

medium🪤 Complexity Trap Q13 of Q15
Greedy Algorithms - Remove K Digits (Smallest Number)
What is the time complexity of the optimal greedy algorithm using a stack to remove k digits from a number string of length n to get the smallest number?
AO(n) because each digit is pushed and popped at most once
BO(n^2) because nested loops are needed to find digits to remove
CO(n log n) due to sorting digits internally
DO(n * k) because each digit can cause up to k pops
Step-by-Step Solution
  1. Step 1: Identify operations per digit

    Each digit is pushed onto the stack once and can be popped at most once when a smaller digit arrives.
  2. Step 2: Analyze total operations

    Since each push and pop happens at most once per digit, total operations are proportional to n.
  3. Final Answer:

    Option A -> Option A
  4. Quick Check:

    Stack operations are linear in n, no nested loops [OK]
Quick Trick: Each digit pushed/popped once -> O(n) time [OK]
Common Mistakes:
MISTAKES
  • Assuming worst case k pops per digit -> O(n*k)
  • Confusing with sorting complexity
  • Thinking nested loops are needed
Trap Explanation:
PITFALL
  • It's tempting to think each digit causes multiple pops, but total pops ≤ n.
Interviewer Note:
CONTEXT
  • Checks if candidate understands amortized analysis of stack operations.
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