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* n)) Approach 2: Greedy min-heap based algorithm (O(n log n)) When might the brute force approach be preferable over the greedy min-heap approach?

hard⚖️ Approach Comparison Q8 of Q15
Greedy Algorithms - Minimum Cost to Connect Sticks
Consider two approaches to solve the minimum cost to connect sticks problem: Approach 1: Brute force trying all merge orders (O(n! * n)) Approach 2: Greedy min-heap based algorithm (O(n log n)) When might the brute force approach be preferable over the greedy min-heap approach?
AWhen n is very small and exact minimum cost is required
BWhen sticks have equal lengths and greedy fails
CWhen sticks can be reused after merging
DWhen n is very large and performance is critical
Step-by-Step Solution
Solution:
  1. Step 1: Compare approaches

    Brute force guarantees exact minimum cost by exploring all merge orders but is factorial time.
  2. Step 2: Identify use case

    For very small n, brute force is feasible and exact; greedy is efficient and also optimal here.
  3. Final Answer:

    Option A -> Option A
  4. Quick Check:

    Brute force only practical for small n [OK]
Quick Trick: Brute force only feasible for small n [OK]
Common Mistakes:
MISTAKES
  • Thinking brute force is better for large n
  • Assuming greedy fails on equal lengths
Trap Explanation:
PITFALL
  • Candidates confuse brute force feasibility or think greedy fails on equal sticks, which it does not.
Interviewer Note:
CONTEXT
  • Tests understanding of trade-offs between brute force and greedy
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