Greedy Algorithms - Minimum Domino Rotations
What is the overall time complexity of the optimal solution that checks only two candidate values for the Minimum Domino Rotations problem on arrays of length n?
What is the overall time complexity of the optimal solution that checks only two candidate values for the Minimum Domino Rotations problem on arrays of length n?
medium📊 Complexity Q5 of Q15
Step-by-Step Solution
Solution:
Step 1: Candidate selection
Only two candidate values (from the first domino) are checked.Step 2: Single pass counting
For each candidate, iterate through arrays once to count rotations.Step 3: Calculate total time
Since each candidate requires O(n) time and there are only two candidates, total time is O(n).Final Answer:
Option A -> Option AQuick Check:
Linear scan twice is linear time. [OK]
Quick Trick: Two passes over arrays yield O(n) complexity [OK]
Common Mistakes:
MISTAKES- Assuming O(n^2) due to nested loops
- Confusing with sorting complexity
- Thinking checking all numbers 1-6 affects complexity here
Trap Explanation:
PITFALL- Mistaking multiple candidate checks or nested loops for higher complexity.
Interviewer Note:
CONTEXT- Evaluates understanding of time complexity in optimized greedy solutions.
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