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Which of the following changes correctly adapts the DP solution to this variant?

hard🎤 Interviewer Follow-up Q15 of Q15
Dynamic Programming: Knapsack - Target Sum
Suppose the Target Sum problem is modified so that each number in the array can be used multiple times (unlimited reuse). Which of the following changes correctly adapts the DP solution to this variant?
AUse a 1D dp array and update dp in forward order for each num to allow reuse
BKeep the same DP with offset and update dp in reverse order to avoid double counting
CUse a 2D dp array with dimensions n and sum, but only update dp[i][s] from dp[i-1][s-num]
DSwitch to a brute force recursion since DP cannot handle reuse
Step-by-Step Solution
  1. Step 1: Understand reuse impact on DP iteration

    Allowing unlimited reuse means for each num, dp must be updated in forward order so that dp[s-num] includes ways using current num multiple times.
  2. Step 2: Identify correct DP update order

    Backward iteration prevents reuse by only using previous states. Forward iteration accumulates counts correctly for unlimited usage.
  3. Step 3: Evaluate options

    Use a 1D dp array and update dp in forward order for each num to allow reuse correctly updates dp forward. Keep the same DP with offset and update dp in reverse order to avoid double counting backward iteration is for no reuse. Use a 2D dp array with dimensions n and sum, but only update dp[i][s] from dp[i-1][s-num] restricts to previous items only. Switch to a brute force recursion since DP cannot handle reuse is inefficient.
  4. Final Answer:

    Option A -> Option A
  5. Quick Check:

    Forward dp update enables multiple usage of same number [OK]
Quick Trick: Forward dp iteration enables unlimited reuse [OK]
Common Mistakes:
MISTAKES
  • Using backward iteration which forbids reuse
Trap Explanation:
PITFALL
  • Backward iteration looks safer but disallows multiple usage, a subtle but critical difference.
Interviewer Note:
CONTEXT
  • Checks candidate's understanding of DP iteration order for reuse variants.
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