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Given the following partial dp array for the Perfect Squares problem: dp = [0,1,2,3,1,2,3,4,2,3,4,5,3], what is the original input n for which this dp was computed?

hard🔄 Reverse Engineer Q9 of Q15
Dynamic Programming: Knapsack - Perfect Squares
Given the following partial dp array for the Perfect Squares problem: dp = [0,1,2,3,1,2,3,4,2,3,4,5,3], what is the original input n for which this dp was computed?
A13
B11
C12
D14
Step-by-Step Solution
Solution:
  1. Step 1: Understand dp array meaning

    dp[i] stores minimal number of perfect squares summing to i.
  2. Step 2: Identify dp length

    dp length is 13, so last index is 12, meaning dp computed up to n=12.
  3. Step 3: Confirm dp[12] value

    dp[12] = 3 matches known minimal count for 12 (4+4+4).
  4. Final Answer:

    Option C -> Option C
  5. Quick Check:

    dp array length - 1 = n -> 12 [OK]
Quick Trick: dp array length minus one equals n [OK]
Common Mistakes:
MISTAKES
  • Misreading dp length
  • Confusing dp indices with values
  • Assuming dp stores sums not counts
Trap Explanation:
PITFALL
  • Candidates often confuse dp array length with n or misinterpret dp meaning.
Interviewer Note:
CONTEXT
  • Tests ability to reverse engineer input from DP state
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