Dynamic Programming: Knapsack - Perfect Squares
If the Perfect Squares problem is changed so that each perfect square can be used at most once, which algorithmic approach is most appropriate?
If the Perfect Squares problem is changed so that each perfect square can be used at most once, which algorithmic approach is most appropriate?
hard⚙️ Functional Understanding Q10 of Q15
Step-by-Step Solution
Solution:
Step 1: Understand the constraint
Each perfect square can be used at most once, so no repeated usage.Step 2: Algorithmic implication
This is a 0/1 knapsack variant, where each item (perfect square) can be chosen once.Step 3: Choose approach
Use 0/1 knapsack DP to track sums achievable with unique perfect squares.Final Answer:
Option B -> Option BQuick Check:
At most once usage means 0/1 knapsack [OK]
Quick Trick: At most once usage means 0/1 knapsack DP [OK]
Common Mistakes:
MISTAKES- Using unbounded knapsack which allows unlimited usage
- Assuming greedy works for minimal count
- Choosing BFS without pruning
Trap Explanation:
PITFALL- Unbounded knapsack looks similar but allows repeated usage
Interviewer Note:
CONTEXT- Tests understanding of knapsack variants and constraints
Master "Perfect Squares" in Dynamic Programming: Knapsack
Want More Practice?
15+ quiz questions · All difficulty levels · Free
Free Signup - Practice All QuestionsMore Dynamic Programming: Knapsack Quizzes