[Solved] Identify the issue in the following Python code that attempts to check if a number is a power of two:def isPowerOfTwo(n: int) -> bool: while n % 2 == 0: n /= 2 return n == 1 | Bit Manipulation

Bit Manipulation - Power of Two

Identify the issue in the following Python code that attempts to check if a number is a power of two:

def isPowerOfTwo(n: int) -> bool:
    while n % 2 == 0:
        n /= 2
    return n == 1

AThe function should return <code>n == 0</code> instead of <code>n == 1</code>

BThe loop condition should be <code>n > 1</code> instead of <code>n % 2 == 0</code>

CThe function does not handle negative numbers correctly

DUsing floating-point division instead of integer division causes incorrect results

Step-by-Step Solution

Solution:

Step 1: Analyze the division operation
The code uses n /= 2, which performs floating-point division in Python 3.
Step 2: Effect on loop and comparison
This converts n to a float, so the loop condition and final comparison n == 1 may fail due to floating-point precision.
Step 3: Correct approach
Use integer division n //= 2 to keep n an integer and ensure correct logic.
Final Answer:
Option D -> Option D
Quick Check:
Use integer division for exact results [OK]

Quick Trick: Use integer division (//) to avoid float errors [OK]

Common Mistakes:

MISTAKES

Trap Explanation:

PITFALL

Interviewer Note:

CONTEXT

Master "Power of Two" in Bit Manipulation

3 interactive learning modes - each teaches the same concept differently

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