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What is the time complexity of the brute force bit counting approach that checks each bit of a 32-bit integer one by one?

medium🪤 Complexity Trap Q13 of Q15
Bit Manipulation - Number of 1 Bits (Hamming Weight)
What is the time complexity of the brute force bit counting approach that checks each bit of a 32-bit integer one by one?
AO(log n) where n is the integer's value
BO(n) where n is the integer's value
CO(1) because the number of bits is fixed (32 bits)
DO(32 * log n) due to bit shifts and counting
Step-by-Step Solution
  1. Step 1: Identify input size

    The input is an integer n, and the brute force method checks each bit by shifting until n becomes zero.
  2. Step 2: Analyze loop iterations

    The number of iterations depends on the number of bits in n, which is proportional to log n.
  3. Final Answer:

    Option A -> Option A
  4. Quick Check:

    Loop runs approximately log n times, so complexity is O(log n) [OK]
Quick Trick: Number of bits in n is proportional to log n [OK]
Common Mistakes:
MISTAKES
  • Assuming fixed bit width means O(1)
  • Confusing value magnitude with fixed bit size
Trap Explanation:
PITFALL
  • Fixed 32-bit size applies only if input size is fixed; if input is arbitrary integer, complexity depends on log n.
Interviewer Note:
CONTEXT
  • Tests understanding of complexity relative to input size and bit operations.
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