If the problem is generalized to find k missing numbers from 1 to n where k > 2, which statement about the XOR partitioning approach is true?

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Bit Manipulation - Find Two Missing Numbers

If the problem is generalized to find k missing numbers from 1 to n where k > 2, which statement about the XOR partitioning approach is true?

AXOR partitioning requires sorting the array first for k > 2

BXOR partitioning works the same way regardless of how many numbers are missing

CXOR partitioning can find k missing numbers in O(k) time

DXOR partitioning cannot be directly extended to find more than two missing numbers efficiently

Step-by-Step Solution

Solution:

Step 1: Understand XOR partitioning for two missing numbers
It relies on XOR of two numbers and partitioning by a set bit.
Step 2: For k > 2 missing numbers
The XOR of k missing numbers does not allow simple partitioning to isolate each missing number.
Step 3: Conclusion
Direct extension is not efficient; other methods like hashing or sum formulas are preferred.
Final Answer:
Option D -> Option D
Quick Check:
XOR works well only for two missing numbers [OK]

Quick Trick: XOR partitioning limited to two missing numbers [OK]

Common Mistakes:

MISTAKES

Trap Explanation:

PITFALL

Interviewer Note:

CONTEXT

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