Bit Manipulation - Maximum XOR of Two Numbers
If the input array contains 64-bit unsigned integers, which modification is necessary in the trie-based maximum XOR algorithm to handle these numbers correctly?
If the input array contains 64-bit unsigned integers, which modification is necessary in the trie-based maximum XOR algorithm to handle these numbers correctly?
hard🔁 Follow-Up Q10 of Q15
Step-by-Step Solution
Solution:
Step 1: Understand bit representation
64-bit numbers require a trie depth of 64 to represent all bits.Step 2: Consequence of insufficient depth
Using fewer levels truncates bits, causing incorrect XOR results.Step 3: Other options
Converting to 32-bit or ignoring bits loses information; floating-point is not suitable.Final Answer:
Option C -> Option CQuick Check:
Trie depth must match bit-length [OK]
Quick Trick: Trie depth equals bit-length of numbers [OK]
Common Mistakes:
MISTAKES- Truncating numbers to 32 bits losing data
- Using floating-point which is incompatible
- Ignoring higher bits assuming no impact
Trap Explanation:
PITFALL- Ignoring bit-length or using incompatible types causes errors.
Interviewer Note:
CONTEXT- Tests understanding of adapting trie depth for larger integer sizes.
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