Bit Manipulation - Maximum Product of Word Lengths
Given the following code snippet and input words = ["abcw", "baz", "foo", "bar", "xtfn"], what is the returned maximum product of word lengths with no common letters?
Given the following code snippet and input words = ["abcw", "baz", "foo", "bar", "xtfn"], what is the returned maximum product of word lengths with no common letters?
easy🧾 Code Trace Q3 of Q15
Step-by-Step Solution
Solution:
Step 1: Compute bitmasks and lengths
"abcw"=4 chars, mask includes a,b,c,w; "xtfn"=4 chars, mask includes x,t,f,n; these two share no letters.Step 2: Check pairs for no overlap and max product
Product of lengths for "abcw" and "xtfn" is 4*4=16, which is the maximum found.Final Answer:
Option D -> Option DQuick Check:
Max product is 16 from "abcw" and "xtfn" [OK]
Quick Trick: Check pairs with no common letters for max product [OK]
Common Mistakes:
MISTAKES- Miscounting word lengths
- Overlooking character overlap in pairs
Trap Explanation:
PITFALL- Candidates often pick pairs with common letters or miscalculate lengths, leading to wrong max product.
Interviewer Note:
CONTEXT- Tests ability to trace bitmasking code on typical input
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