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How would you extend the bitwise sum algorithm to add two arbitrarily large integers represented as strings without using '+' or '-' operators?

hard🎤 Interviewer Follow-up Q10 of Q15
Bit Manipulation - Sum of Two Integers Without + Operator
How would you extend the bitwise sum algorithm to add two arbitrarily large integers represented as strings without using '+' or '-' operators?
AConvert strings to integers and use built-in '+' operator
BSimulate addition digit-by-digit with carry using bitwise operations on each digit
CUse bitwise sum on integer conversions after truncating to 32 bits
DUse floating-point arithmetic to approximate the sum
Step-by-Step Solution
Solution:
  1. Step 1: Recognize limitation of bitwise sum on fixed-size integers

    Bitwise sum works on fixed-width integers; arbitrarily large integers exceed this size.
  2. Step 2: Consider digit-by-digit addition

    Simulating addition digit-by-digit with bitwise ops on each digit is required, not direct bitwise sum on entire number.
  3. Step 3: Floating-point arithmetic is not suitable for exact large integer sums

    Therefore, simulating addition digit-by-digit with carry using bitwise operations on each digit is correct; using floating-point arithmetic to approximate the sum is incorrect.
  4. Final Answer:

    Option B -> Option B
  5. Quick Check:

    Digit-wise addition with carry simulates large integer sum [OK]
Quick Trick: Large integer addition requires digit-wise simulation [OK]
Common Mistakes:
MISTAKES
  • Trying to apply bitwise sum directly on large strings
Trap Explanation:
PITFALL
  • Candidates incorrectly assume bitwise sum scales to arbitrarily large integers.
Interviewer Note:
CONTEXT
  • Tests ability to adapt bitwise sum to large integer addition
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