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Consider two approaches to compute bitwise AND of numbers range: (1) Brute force iteration over the range, and (2) shifting both numbers until equal. When is approach (2) clearly better than (1)?

hard⚖️ Approach Comparison Q8 of Q15
Bit Manipulation - Bitwise AND of Numbers Range
Consider two approaches to compute bitwise AND of numbers range: (1) Brute force iteration over the range, and (2) shifting both numbers until equal. When is approach (2) clearly better than (1)?
AWhen the range size is large but numbers share a long common prefix
BWhen left and right are equal
CWhen the range size (right - left) is very small
DWhen the numbers are very small integers
Step-by-Step Solution
Solution:
  1. Step 1: Understand brute force iterates over all numbers in range

    Its time complexity is O(right - left), which is slow for large ranges.
  2. Step 2: Shifting approach runs in O(log right) and benefits when numbers share many prefix bits

    Long common prefix means fewer shifts and faster computation.
  3. Final Answer:

    Option A -> Option A
  4. Quick Check:

    Large ranges with common prefix favor shifting approach [OK]
Quick Trick: Shifting approach exploits common prefix for speed [OK]
Common Mistakes:
MISTAKES
  • Assuming brute force is always better for small ranges
  • Ignoring common prefix impact
Trap Explanation:
PITFALL
  • Candidates often overlook that shifting approach is better when common prefix is long, not just small ranges.
Interviewer Note:
CONTEXT
  • Tests tradeoff reasoning between brute force and bit manipulation.
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