Bit Manipulation - Bitwise AND of Numbers Range
Which technique efficiently computes the bitwise AND of all integers between
left and right without checking each number individually?Which technique efficiently computes the bitwise AND of all integers between left and right without checking each number individually?
easy🔍 Problem Recognition Q1 of Q15
Step-by-Step Solution
Solution:
Step 1: Identify common prefix
Bitwise AND of a range zeros out bits that differ betweenleftandright. The common prefix bits remain.Step 2: Shift to find prefix
Right shift both numbers until they are equal, recording the number of shifts.Step 3: Shift back
Left shift the common prefix back by the number of shifts to get the final result.Final Answer:
Option D -> Option DQuick Check:
Common prefix approach avoids iteration [OK]
Quick Trick: Find common binary prefix of left and right [OK]
Common Mistakes:
MISTAKES- Trying to AND all numbers individually
- Using sum or XOR which do not preserve AND properties
- Ignoring bit shifts and common prefix
Trap Explanation:
PITFALL- Sum or XOR do not yield bitwise AND results, tempting but incorrect.
Interviewer Note:
CONTEXT- Tests understanding of bitwise AND range pattern and efficient approach.
Master "Bitwise AND of Numbers Range" in Bit Manipulation
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