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Tabular Puzzle

Introduction

The Tabular Puzzle asks you to organise multi-attribute data (people, places, jobs, colours, months, etc.) into a table using given clues. This pattern trains systematic elimination, linking clues across attributes, and accurate final matching.

It is widely tested in competitive exams (SBI PO, IBPS, SSC, CAT) because it evaluates careful deduction and attention to detail. Good table design and stepwise elimination make these problems straightforward and reproducible.

Pattern: Tabular Puzzle

Pattern

Convert clues into table entries and use elimination + linking to fill every cell.

  • Represent each entity (person/item) as a row; attributes (city, job, day) are columns.
  • Mark direct facts first, then apply “not” clues to eliminate options.
  • Use linking clues (e.g., “the person from X is a Y”) to lock two attributes together.
  • Iterate: filling one cell often forces others - keep the table updated.

Step-by-Step Example

Question

Four friends - A, B, C, and D - live in different cities: Delhi, Mumbai, Kolkata, and Chennai. Each works in a different profession: Doctor, Engineer, Teacher, and Lawyer.

Clues:

  1. B is not from Delhi or Chennai.
  2. The person from Kolkata is a Teacher.
  3. D is a Lawyer and does not live in Mumbai.
  4. A lives in Delhi.

Question: Who lives in Chennai?

Options:
A) B    B) C    C) D    D) A

Solution

  1. Step 1: Mark direct facts

    A → Delhi; D → Lawyer; D ≠ Mumbai; Kolkata → Teacher (city-profession link).

  2. Step 2: Build an initial table (partial)

    PersonCityProfession
    ADelhi-
    BNot Delhi, Not Chennai-
    C-Teacher (if Kolkata)
    DNot MumbaiLawyer

  3. Step 3: Apply elimination and linking

    B cannot be Delhi/Chennai → B must be Mumbai or Kolkata. D is not Mumbai and is Lawyer → D cannot be Kolkata (because Kolkata → Teacher). A is Delhi → remaining cities: Mumbai, Kolkata, Chennai for B, C, D. Since Kolkata → Teacher and D is Lawyer, C must be Kolkata & Teacher.

  4. Step 4: Complete the final table

    PersonCityProfession
    ADelhiEngineer
    BMumbaiDoctor
    CKolkataTeacher
    DChennaiLawyer

  5. Final Answer:

    D (D lives in Chennai) → Option C

  6. Quick Check:

    A = Delhi ✅; D = Lawyer and ≠ Mumbai → D = Chennai ✅; Kolkata → Teacher → C = Kolkata & Teacher ✅; B cannot be Delhi/Chennai → B = Mumbai ✅

Quick Variations

1. Two-attribute tables: Person × City.

2. Three-attribute tables: Person × City × Profession (use 2D grid with linked cells).

3. Conditional tables: include "either-or", "exactly one matches" clues.

4. Larger tables (5×5): use progressive elimination and intermediate partial tables.

Trick to Always Use

  • Step 1: Create a clear table and mark direct facts first (use ticks / 'not' marks mentally).
  • Step 2: Lock any two-attribute links (e.g., Kolkata = Teacher) early - they reduce choices faster.
  • Step 3: Fill forced cells next; each forced fill cascades into more eliminations.
  • Step 4: Use a final table in the solution to present the completed mapping clearly.

Summary

Summary

  • Start by marking direct facts and obvious 'not' entries in a grid.
  • Lock combined clues (city-profession) early to reduce possibilities.
  • Iteratively fill forced cells; keep the table updated after each step.
  • Use a final table in your solution - it makes verification quick and foolproof.

Example to remember:
When a clue links two attributes (e.g., Kolkata = Teacher), assign that pair first - then eliminate that city and profession for others.

Practice

(1/5)
1. Four friends - A, B, C, and D - each like a different color (Red, Blue, Green, Yellow) and drive a different car (Honda, Ford, Tata, Maruti). The clues are:<br>1. A likes Red and does not drive Ford.<br>2. The person who drives Tata likes Green.<br>3. D drives Maruti.<br>4. B does not like Yellow or Green.<br>Who drives the Ford?
easy
A. B
B. C
C. D
D. A

Solution

  1. Step 1: Note direct facts

    A → Red, not Ford; D → Maruti; Tata → Green.

  2. Step 2: Partial table from given facts

    PersonColorCar
    ARedNot Ford
    BNot Yellow/Green-
    CGreenTata
    D-Maruti

  3. Step 3: Apply eliminations

    B cannot be Yellow/Green, so B = Blue. A already has Red → remaining colors match correctly. Since Ford is not used yet and A ≠ Ford → Ford = B.

  4. Step 4: Final table

    PersonColorCar
    ARedHonda
    BBlueFord
    CGreenTata
    DYellowMaruti

  5. Final Answer:

    B → Option A

  6. Quick Check:

    All clues consistent ✅
Hint: Start with fixed pairs and direct negatives before using eliminations.
Common Mistakes: Ignoring 'not' clues early, leading to overlap errors.
2. Five employees - P, Q, R, S, and T - work in five departments: HR, IT, Finance, Marketing, and Admin. The clues are:<br>1. Q works in IT.<br>2. P works neither in HR nor in Admin.<br>3. The Marketing employee sits next to HR.<br>4. R works in Finance.<br>5. T does not work in Marketing.<br>Who works in Marketing?
easy
A. S
B. P
C. T
D. Q

Solution

  1. Step 1: Fixed data

    Q = IT; R = Finance.

  2. Step 2: Partial table

    EmployeeDepartment
    PNot HR/Admin
    QIT
    RFinance
    S-
    TNot Marketing

  3. Step 3: Deduction

    P ≠ HR/Admin → possible: IT/Finance/Marketing. IT, Finance taken → P = Marketing.

  4. Step 4: Final table

    EmployeeDepartment
    PMarketing
    QIT
    RFinance
    SHR
    TAdmin

  5. Final Answer:

    P → Option B

  6. Quick Check:

    P not HR/Admin ✅, Marketing next to HR ✅
Hint: Use exclusion clues before adjacency clues.
Common Mistakes: Treating ‘next to HR’ as same department.
3. Four students - A, B, C, and D - study four subjects: Maths, Physics, Chemistry, and Biology. The clues are:<br>1. A does not study Maths or Physics.<br>2. C studies Chemistry.<br>3. D studies a subject alphabetically before C’s.<br>4. B does not study Biology.<br>Who studies Physics?
medium
A. A
B. D
C. C
D. B

Solution

  1. Step 1: Direct clues

    C = Chemistry; A ≠ Maths/Physics → A = Biology.

  2. Step 2: Partial table

    StudentSubject
    ABiology
    BNot Biology
    CChemistry
    D-

  3. Step 3: Apply alphabetical rule

    D’s subject alphabetically before Chemistry → only Maths fits. D = Maths.

  4. Step 4: Fill remaining

    Subjects used: Bio, Chem, Maths → remaining Physics → B = Physics.

  5. Final Table:

    StudentSubject
    ABiology
    BPhysics
    CChemistry
    DMaths

  6. Final Answer:

    B → Option D

  7. Quick Check:

    Alphabetical before Chemistry → D = Maths ✅
Hint: Alphabetical hints often give hidden order of assignment.
Common Mistakes: Overlooking implicit alphabetical constraints.
4. Four athletes - P, Q, R, and S - play four different sports: Cricket, Football, Tennis, and Hockey. The clues are:<br>1. P does not play Tennis.<br>2. The Football player’s name alphabetically follows the Tennis player.<br>3. R plays Cricket.<br>4. Q’s name comes alphabetically before the Hockey player’s.<br>Who plays Tennis?
medium
A. P
B. Q
C. R
D. S

Solution

  1. Step 1: Fixed fact

    R = Cricket.

  2. Step 2: Partial table

    AthleteSport
    PNot Tennis
    Q-
    RCricket
    S-

  3. Step 3: Test alphabetical relations

    If Q = Tennis → Football must follow alphabetically → choose S = Football; Hockey after Q → assign P = Hockey.

  4. Step 4: Final Table

    AthleteSport
    PHockey
    QTennis
    RCricket
    SFootball

  5. Final Answer:

    Q → Option B

  6. Quick Check:

    Tennis (Q) alphabetically before Football (S) ✅
Hint: Use alphabetical order as a hidden sequencing clue.
Common Mistakes: Misreading alphabetical relation as performance ranking.
5. Five friends - A, B, C, D, and E - each own a different pet (Dog, Cat, Parrot, Fish, Rabbit) and live in different cities (Delhi, Mumbai, Chennai, Kolkata, Pune). The clues are:<br>1. A lives in Mumbai and owns a Parrot.<br>2. The person from Chennai owns a Dog.<br>3. D lives in Delhi.<br>4. C owns a Cat.<br>5. E does not live in Pune or Chennai.<br>Who owns the Fish?
medium
A. B
B. D
C. E
D. C

Solution

  1. Step 1: Direct mapping

    A = Mumbai + Parrot; D = Delhi; C = Cat; Chennai → Dog.

  2. Step 2: Partial table

    PersonCityPet
    AMumbaiParrot
    B--
    CChennaiCat
    DDelhiDog
    ENot Pune/Chennai-

  3. Step 3: Fill remaining

    E cannot be Pune or Chennai → E = Kolkata. Remaining pets → Fish & Rabbit → assign E = Fish, B = Rabbit.

  4. Step 4: Final Table

    PersonCityPet
    AMumbaiParrot
    BPuneRabbit
    CChennaiCat
    DDelhiDog
    EKolkataFish

  5. Final Answer:

    E → Option C

  6. Quick Check:

    Each city and pet uniquely assigned ✅
Hint: Start with fixed city-pet pairs to reduce variables quickly.
Common Mistakes: Assigning E to a restricted city.

Mock Test

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