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Relative Movement Problems

Introduction

Relative Movement Problems involve two or more people/objects moving simultaneously or sequentially in different directions. The goal is to determine their relative positions, directions, distances between them, or who is to the left/right of whom after movements. These questions appear frequently in reasoning tests and require careful vector thinking and relative-frame reasoning.

This pattern is important because it trains you to compare multiple trajectories, use cancellations, and reason about positions from different reference points - skills that improve spatial intuition and exam performance.

Pattern: Relative Movement Problems

Pattern

Key concept: Treat each person's path as a vector (horizontal and vertical components). Compute final coordinates relative to a common origin, then compare coordinates to answer relative-position questions (e.g., who is north/east of whom, distances, or facing relations).

Quick rules:

  • Choose a convenient origin (often one person's start point) and use consistent axes: North = +y, South = -y, East = +x, West = -x.
  • Translate each movement into x/y changes and sum them to get final coordinates.
  • Compare coordinates pairwise: x larger → more east; y larger → more north.
  • Distance between two points = √((Δx)² + (Δy)²).
  • For relative facing questions, track orientations separately from positions; turns affect facing, not coordinates.

Step-by-Step Example

Question

How to solve: Two friends A and B start at the same point. A walks 4 m North then 6 m East. B walks 3 m East then 5 m North. After these moves, who is farther East and what is the distance between them?

Solution

  1. Step 1: Choose origin & axes

    Place the common start at (0,0). Use x for East (+), y for North (+).
  2. Step 2: Convert A’s movements to coordinates

    A: 4 m North → (0, +4). Then 6 m East → (0+6, 4) = (6, 4).
  3. Step 3: Convert B’s movements to coordinates

    B: 3 m East → (3, 0). Then 5 m North → (3, 5) = (3, 5).
  4. Step 4: Compare East (x) coordinates

    A’s x = 6, B’s x = 3 → A is farther East.
  5. Step 5: Distance between A and B

    Δx = 6 - 3 = 3; Δy = 4 - 5 = -1. Distance = √(3² + (-1)²) = √(9 + 1) = √10 ≈ 3.16 m.
  6. Final Answer:

    A is farther East, and the distance between them is √10 ≈ 3.16 m.
  7. Quick Check:

    Compare coordinates visually: A(6,4) right of B(3,5) by 3 units and 1 unit south → diagonal distance √10 ✅

Quick Variations

1. Simultaneous movement in different starting points - translate both to global coordinates first.

2. Questions asking “who faces whom” - compute final positions then reason about facing using relative bearings.

3. Some problems involve return paths or loops; treat each leg sequentially and sum vectors.

4. Time-staggered movement (A moves, then B starts) - still compute final coordinates at the relevant times for comparison.

5. Combine with turns/rotations: track both position (vector) and facing (orientation) separately.

Trick to Always Use

  • Step 1: Fix an origin and axis convention (x = East, y = North).
  • Step 2: Convert every move into (Δx, Δy); add them sequentially per person.
  • Step 3: For comparisons: larger x → more east; larger y → more north. For distance, use Pythagoras.
  • Step 4: Draw a tiny diagram with labeled coordinates - it catches sign errors quickly.

Summary

Summary

For Relative Movement Problems:

  • Always convert movements to coordinate changes.
  • Compute final positions separately for each person/object.
  • Compare coordinates to answer relative-location questions; use √(Δx²+Δy²) for distances.
  • Keep position (vector) and facing (orientation) tracked separately when turns are involved.
  • Quick diagram + axis convention prevents sign mistakes and speeds up solving.

Practice

(1/5)
1. A and B start from the same point. A walks 6 m North and 8 m East. B walks 8 m North and 6 m East. Where is A with respect to B?
easy
A. √8 m South-East
B. √8 m North-West
C. √8 m South-West
D. √8 m North-East

Solution

  1. Step 1: Represent positions on a coordinate plane

    A = (8, 6); B = (6, 8).
  2. Step 2: Compute relative vector (A from B)

    Δx = 8 - 6 = +2 (East), Δy = 6 - 8 = -2 (South).
  3. Step 3: Interpret signs

    (+x, -y) → South-East direction.
  4. Step 4: Distance

    Distance = √(2² + (-2)²) = √8 ≈ 2.83 m.
  5. Final Answer:

    √8 m South-East → Option A
  6. Quick Check:

    A is 2 m east and 2 m south of B → √(2² + 2²) = √8 ✅
Hint: Subtract B’s coordinates from A’s to find direction; use √(Δx² + Δy²) for exact distance.
Common Mistakes: Labeling as '2 m' instead of √8 m, or reversing A-B reference.
2. P and Q start from the same point. P walks 10 m North and 5 m East, while Q walks 10 m East and 5 m North. What is the direction of Q from P?
easy
A. North-East
B. South-West
C. South-East
D. North-West

Solution

  1. Step 1: Represent coordinates

    P = (5, 10), Q = (10, 5).
  2. Step 2: Find relative difference

    Q - P = (10 - 5, 5 - 10) = (5, -5).
  3. Step 3: Interpret signs

    +x = East, -y = South → South-East direction.
  4. Step 4: Distance

    Distance = √(5² + 5²) = √50 ≈ 7.07 m.
  5. Final Answer:

    South-East → Option C
Hint: Positive x and negative y = South-East.
Common Mistakes: Mixing up ‘Q from P’ vs ‘P from Q’.
3. Two friends A and B start from the same point. A walks 4 m North and 3 m East. B walks 4 m East and 3 m North. How far apart are they?
easy
A. 2 m
B. √2 m
C. 1 m
D. √5 m

Solution

  1. Step 1: Determine coordinates

    A = (3, 4); B = (4, 3).
  2. Step 2: Calculate displacement

    Δ = (4 - 3, 3 - 4) = (1, -1).
  3. Step 3: Distance

    Distance = √(1² + (-1)²) = √2 ≈ 1.41 m.
  4. Final Answer:

    √2 m → Option B
Hint: Equal legs swapped → always √2 apart.
Common Mistakes: Adding coordinates instead of subtracting.
4. R and S start from different points. R walks 6 m East, then 8 m North. S starts 4 m North of R’s starting point and walks 8 m East. What is S’s position relative to R?
medium
A. 2 m East and 4 m South
B. 2 m North-West
C. 2 m North-East
D. 2 m South-West

Solution

  1. Step 1: Set coordinates (R’s start = origin)

    R final = (6, 8). S starts at (0, 4) and walks 8 m East → S final = (8, 4).
  2. Step 2: Relative vector (S from R)

    Δ = S - R = (8 - 6, 4 - 8) = (2, -4).
  3. Step 3: Interpret components

    Δx = +2 → 2 m East; Δy = -4 → 4 m South.
  4. Step 4: Distance

    Distance = √(2² + 4²) = √20 ≈ 4.47 m.
  5. Final Answer:

    2 m East and 4 m South → Option A
Hint: Visualize both on a coordinate grid before comparing.
Common Mistakes: Mixing R from S vs S from R relation.
5. Two cyclists start from the same point. One rides 10 km North and the other 10 km East. What is the distance between them?
medium
A. 20√2 km
B. 14 km
C. 12 km
D. 10√2 km

Solution

  1. Step 1: Identify perpendicular displacements

    One cyclist at (0,10), the other at (10,0) → right-angled triangle.
  2. Step 2: Apply Pythagoras theorem

    Distance = √(10² + 10²) = √200 = 10√2 km.
  3. Step 3: Approximation

    10√2 ≈ 14.14 km.
  4. Final Answer:

    10√2 km → Option D
Hint: Equal perpendicular distances → multiply by √2.
Common Mistakes: Adding instead of using the diagonal formula.

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