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Letter Position Value Coding

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Introduction

Letter Position Value Coding converts letters into their alphabetical ranks (A = 1, B = 2, …, Z = 26). This pattern is widely used in reasoning sections to test your speed with simple letter→number mappings and basic manipulations (concatenation, sums, differences).

Pattern: Letter Position Value Coding

Pattern: Letter Position Value Coding

The key concept is: each letter is represented by its position in the alphabet (A = 1, B = 2, …, Z = 26). The code may present these positions as a concatenated number, a sum, or used in arithmetic operations - always confirm the exact output format from the example(s).

Essentials to remember:

  • Position basis: A = 1 through Z = 26 (one-based indexing).
  • Representation styles: Concatenation (e.g., BAD → 214), summation (e.g., BAD → 2+1+4 = 7), or other arithmetic (product, difference, average).
  • Multi-digit handling: When concatenating, maintain the digits for each letter (e.g., J = 10 so AJ = 110 when concatenated as A(1)J(10)).
  • Wrap/Bounds: Positions are fixed 1-26; no wrap-around applies here (unlike shift codes). If the pattern uses modular arithmetic, it will be shown in examples.

Step-by-Step Example

Question

In a code A = 1, B = 2, C = 3, … Z = 26. If BAD = ?
Options:
A. 214    B. 7    C. 2,1,4    D. 204

Solution

  1. Step 1: Identify how the example represents letters

    Check the sample mapping: letters are given by their alphabetical positions (A = 1, B = 2, C = 3). The options include both concatenation (214) and sum (7) forms, so confirm from options which style the code expects.
  2. Step 2: Convert each letter to its position

    B → 2, A → 1, D → 4.
  3. Step 3: Match to the representation style

    The option A shows concatenation of positions as a single number: 2 then 1 then 4 → 214. Option B shows sum 2+1+4 = 7. Since concatenation (214) is explicitly present and aligns with the most literal interpretation when letters are written side-by-side, choose concatenation if the question’s examples use that style. Here options include both forms; concatenation is the intended coding style.
  4. Final Answer:

    214 → Option A
  5. Quick Check:

    Re-convert 214 into letter positions: 2 (B), 1 (A), 4 (D) → BAD ✅. (If the code had meant sum, option B would match; always confirm representation from examples.)

Quick Variations

1. Sum form: Use sum of positions (e.g., BAD → 2+1+4 = 7).

2. Concatenation with separators: Positions shown with commas (e.g., BAD → 2,1,4).

3. Fixed-width concatenation: Use two-digit fixed width for all letters (e.g., A→01, J→10 so AJ → 0110).

4. Derived arithmetic: Use average, product, or difference of positions (e.g., (2+1+4)/3).

Trick to Always Use

  • Step 1 → Decide representation (concatenation vs sum) by scanning options & examples first.
  • Step 2 → Use a quick mental alphabet table for A-Z = 1-26 (memorise common ones: J=10, K=11, T=20, Z=26).

Summary

  • Convert letters using A = 1 through Z = 26 (one-based indexing).
  • Confirm whether the code expects concatenation, summation, or another arithmetic output from the examples/options.
  • For concatenation watch multi-digit letters (J=10, K=11) - decide whether fixed-width or plain concatenation is used.
  • Quick-check by reversing the conversion (numbers → positions → letters) to ensure correctness.

Example to remember:
BAD → 2,1,4 → concatenated as 214 (if concatenation is the chosen representation) or summed as 7 (if sum-style).

Practice

(1/5)
1. Using A=1, B=2, … Z=26 (concatenate the position values without separators), what is JAR = ?
easy
A. 10118
B. 1118
C. 101118
D. 10-1-18

Solution

  1. Step 1: Convert each letter to its position

    J → 10, A → 1, R → 18.
  2. Step 2: Concatenate the position values (no separators)

    Write them side-by-side: 10 then 1 then 18 → 10118.
  3. Final Answer:

    10118 → Option A
  4. Quick Check:

    Split 10118 into 10 | 1 | 18 → J | A | R ✅
Hint: When concatenating, keep multi-digit positions intact (J=10 stays as ‘10’).
Common Mistakes: Dropping leading digits or inserting separators when not required.
2. Using A=1, B=2, … Z=26 (sum of positions), what is SUM = ?
easy
A. 52
B. 53
C. 54
D. 51

Solution

  1. Step 1: Convert letters to positions

    S → 19, U → 21, M → 13.
  2. Step 2: Add the positions

    19 + 21 + 13 = 53 → 53.
  3. Final Answer:

    53 → Option B
  4. Quick Check:

    Verify addition: 19 + 21 = 40; 40 + 13 = 53 ✅
Hint: Add the largest two first to reduce arithmetic errors.
Common Mistakes: Forgetting to convert letters correctly (e.g., S=18 instead of 19).
3. If positions are written in fixed two-digit format (A = 01, B = 02, …, Z = 26) and concatenated, what is AGE = ?
easy
A. 010705
B. 10705
C. 01070500
D. 0107050

Solution

  1. Step 1: Convert letters using two-digit fixed width

    A → 01, G → 07, E → 05.
  2. Step 2: Concatenate the two-digit blocks

    01 | 07 | 05 → 010705.
  3. Final Answer:

    010705 → Option A
  4. Quick Check:

    Split 010705 into 01,07,05 → A,G,E ✅
Hint: Use fixed two-digit blocks so J (10) and A (01) remain unambiguous.
Common Mistakes: Dropping the leading zero for single-digit positions.
4. Using A=1, B=2, … Z=26 and representing positions with commas, what is CAT = ?
medium
A. 3-1-20
B. 3;1;20
C. 3,1,20
D. 03,01,20

Solution

  1. Step 1: Convert each letter to its position

    C → 3, A → 1, T → 20.
  2. Step 2: Represent the positions using commas as separators

    3,1,20 → 3,1,20.
  3. Final Answer:

    3,1,20 → Option C
  4. Quick Check:

    Read positions back: 3→C, 1→A, 20→T ✅
Hint: Match the separator style required (comma, hyphen, fixed-width) from the question.
Common Mistakes: Using fixed-width format when commas are requested, or vice versa.
5. Using A=1, B=2, … Z=26, a code is defined as 'product of positions of first and last letters'. What is KEY coded as?
medium
A. 165
B. 2750
C. 250
D. 275

Solution

  1. Step 1: Identify first and last letter positions

    For KEY: first letter K → 11; last letter Y → 25.
  2. Step 2: Compute product of the two positions

    11 × 25 = 275 → 275.
  3. Final Answer:

    275 → Option D
  4. Quick Check:

    Verify multiplication: 11 × 25 = (11 × 20) + (11 × 5) = 220 + 55 = 275 ✅
Hint: Multiply first and last letter values; use 11×25 = 275 as a quick mental pattern.
Common Mistakes: Using sum instead of product or including middle letters in the product.