Step-by-Step SolutionStep 1: Break 2,500 = 400×6 + 100Six 400-year cycles → 6×0 = 0 odd days.Step 2: Remaining 100 years100 years = 5 odd days.Step 3: Reduce modulo 75 mod 7 = 5.Final Answer:5 odd days → Option DQuick Check:2500 = 2400+100 → only 100 contributes → 5 odd days.Quick Trick: Always peel off 400-year cycles → they add 0 odd days.Common Mistakes:MISTAKESSaying 25×100 → 125 odd days without mod 7 reduction.
Master "Calendar Problems" in Reasoning AbilityStart learning the concept with an interactive lesson.Learn
More Reasoning Ability Quizzes Calendar Problems - Leap Year Day Shift Pattern - Quiz 9hard Calendar Problems - Century Code & Day Formula (Zeller’s Rule) - Quiz 8medium Calendar Problems - Month–Date Relationship - Quiz 4easy Calendar Problems - Leap Year Identification - Quiz 1easy Calendar Problems - Counting Days Between Two Dates - Quiz 12easy Calendar Problems - Century Code & Day Formula (Zeller’s Rule) - Quiz 4medium Calendar Problems - Day of the Week (Future/Past Days) - Quiz 15medium Calendar Problems - Reverse Calendar Problem - Quiz 1easy Calendar Problems - Yearly Day Shift - Quiz 13easy Calendar Problems - Leap Year Identification - Quiz 13medium