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Weighted Mean and SD

Introduction

Weighted mean and weighted standard deviation are used when different observations have different importance (weights or frequencies). Instead of treating every value equally, each observation is multiplied by its weight - common in marks with different weightage, inventory with varying counts, or grouped frequency tables.

This pattern is important because it gives a more accurate central value and spread when data points contribute unequally.

Pattern: Weighted Mean and SD

Pattern

The key concept: Use weights to compute a weighted average; compute weighted squared deviations to find weighted variance and then take square root for weighted SD.

Formulas:
Weighted mean (μ) = (Σ wᵢ × xᵢ) ÷ (Σ wᵢ)
Weighted variance (σ²) = (Σ wᵢ × (xᵢ - μ)²) ÷ (Σ wᵢ)
Weighted standard deviation (σ) = √[ (Σ wᵢ × (xᵢ - μ)²) ÷ (Σ wᵢ) ]

Notes:
• If weights are frequencies, these formulas are identical to grouped-data formulas.
• Use population form (divide by Σw) for aptitude problems unless asked to use sample correction.

Step-by-Step Example

Question

A test has three sections with scores and weights as follows: Section A score = 80 (weight 2), Section B score = 70 (weight 3), Section C score = 90 (weight 1). Find the weighted mean and weighted standard deviation.

Solution

  1. Step 1: Identify values and weights

    Observations x: 80, 70, 90.
    Corresponding weights w: 2, 3, 1.

  2. Step 2: Compute weighted mean μ

    Σ wᵢ = 2 + 3 + 1 = 6.
    Σ wᵢ × xᵢ = (2×80) + (3×70) + (1×90) = 160 + 210 + 90 = 460.
    Weighted mean μ = 460 ÷ 6 = 76.67 (rounded to 2 decimals).

  3. Step 3: Compute deviations (xᵢ - μ) and squared deviations

    For 80: deviation = 80 - 76.67 = 3.33 → squared = 11.09 → weighted = 2 × 11.09 = 22.18.
    For 70: deviation = 70 - 76.67 = -6.67 → squared = 44.49 → weighted = 3 × 44.49 = 133.47.
    For 90: deviation = 90 - 76.67 = 13.33 → squared = 177.69 → weighted = 1 × 177.69 = 177.69.

  4. Step 4: Sum weighted squared deviations and compute variance

    Σ wᵢ × (xᵢ - μ)² = 22.18 + 133.47 + 177.69 = 333.34.
    Weighted variance σ² = 333.34 ÷ Σw = 333.34 ÷ 6 = 55.56.

  5. Step 5: Weighted standard deviation

    Weighted SD σ = √55.56 ≈ 7.45.

  6. Final Answer:

    Weighted mean ≈ 76.67, Weighted SD ≈ 7.45.

  7. Quick Check:

    The weighted mean is pulled more toward Section B (higher weight 3) where score is 70, so mean < 80 and >70 - 76.67 is sensible. SD shows moderate spread given one high (90) and one low (70) value. ✅

Quick Variations

1. If all weights are equal, weighted mean reduces to simple arithmetic mean and weighted SD reduces to usual SD.

2. For grouped frequency tables, treat frequency as weight for each class midpoint.

3. If weights sum to 1 (probability weights), same formulas apply; Σw = 1 simplifies variance denominator.

Trick to Always Use

  • Step 1: Always compute Σw first - it is the divisor for both mean and variance.
  • Step 2: Compute Σ(w×x) to get weighted mean quickly.
  • Step 3: Use Σ(w×(x - μ)²) for variance; don’t forget to multiply squared deviations by their weights before summing.

Summary

Summary

In the Weighted Mean and SD pattern:

  • Weighted mean = Σ(w×x) ÷ Σw - weights shift the centre toward more important observations.
  • Weighted variance = Σ[w×(x - μ)²] ÷ Σw; weighted SD = sqrt of this variance.
  • Frequencies are a special case of weights; use the same steps for grouped data.
  • Always multiply squared deviations by weights before summing - this is the most common source of error.

Practice

(1/5)
1. Find the weighted mean of scores 80, 70, 90 with weights 2, 3 and 1 respectively.
easy
A. 76.67
B. 77.50
C. 75.00
D. 74.33

Solution

  1. Step 1: Identify values and weights

    Scores: 80, 70, 90. Weights: 2, 3, 1.

  2. Step 2: Compute Σ(w×x) and Σw

    Σ(w×x) = (2×80) + (3×70) + (1×90) = 160 + 210 + 90 = 460.
    Σw = 2 + 3 + 1 = 6.

  3. Step 3: Weighted mean

    Weighted mean = 460 ÷ 6 = 76.666… ≈ 76.67.

  4. Final Answer:

    76.67 → Option A.

  5. Quick Check:

    Result lies between lowest (70) and highest (90) and is pulled toward the score with larger weight (70) - sensible ✅

Hint: Compute Σ(w×x) then divide by Σw.
Common Mistakes: Forgetting to sum weights or using equal weights by mistake.
2. Given grouped data midpoints 10, 20, 30 with frequencies 2, 3, 5 respectively, find the mean (use frequencies as weights).
easy
A. 22.00
B. 23.00
C. 21.50
D. 24.00

Solution

  1. Step 1: Treat frequencies as weights

    Values x: 10, 20, 30. Weights f: 2, 3, 5.

  2. Step 2: Compute Σ(f×x) and Σf

    Σ(f×x) = (2×10) + (3×20) + (5×30) = 20 + 60 + 150 = 230.
    Σf = 2 + 3 + 5 = 10.

  3. Step 3: Weighted mean

    Mean = 230 ÷ 10 = 23.00.

  4. Final Answer:

    23.00 → Option B.

  5. Quick Check:

    Most weight is on 30 so mean > 20 - 23 fits ✅

Hint: Frequencies act as weights; use Σ(f×x)/Σf.
Common Mistakes: Dividing by number of classes instead of total frequency.
3. Find the weighted standard deviation for values 2, 4, 6 with weights 1, 1, 2 respectively (round to 2 decimals).
medium
A. 1.50
B. 1.25
C. 1.80
D. 1.66

Solution

  1. Step 1: Compute weighted mean

    Σ(w×x) = (1×2)+(1×4)+(2×6)=2+4+12=18. Σw = 1+1+2=4.
    Weighted mean μ = 18 ÷ 4 = 4.5.

  2. Step 2: Compute weighted squared deviations

    For 2: (2-4.5)² = 6.25 → weighted = 1×6.25 = 6.25.
    For 4: (4-4.5)² = 0.25 → weighted = 1×0.25 = 0.25.
    For 6: (6-4.5)² = 2.25 → weighted = 2×2.25 = 4.50.
    Σw×(x-μ)² = 6.25 + 0.25 + 4.50 = 11.00.

  3. Step 3: Weighted variance & SD

    Variance = 11.00 ÷ Σw = 11.00 ÷ 4 = 2.75.
    SD = √2.75 ≈ 1.6583 ≈ 1.66.

  4. Final Answer:

    1.66 → Option D.

  5. Quick Check:

    SD small since values are close; heavier weight on 6 pulls mean up - calculation consistent ✅

Hint: Compute μ first, then Σ[w×(x-μ)²] ÷ Σw, then square-root.
Common Mistakes: Forgetting to multiply squared deviations by weights before summing.
4. An exam has three sections with weights 30%, 30%, 40%. Scores: 78, 82, 90. Find the weighted mean score.
medium
A. 84.00
B. 83.40
C. 82.60
D. 85.00

Solution

  1. Step 1: Convert percentage weights to decimals

    Weights: 0.30, 0.30, 0.40.

  2. Step 2: Compute weighted sum

    Weighted sum = 0.30×78 + 0.30×82 + 0.40×90 = 23.4 + 24.6 + 36 = 84.0.

  3. Step 3: Weighted mean

    Weighted mean = 84.0 (weights sum to 1).

  4. Final Answer:

    84.00 → Option A.

  5. Quick Check:

    Highest weight on 90 pulls mean upward; 84 is between 82 and 90 - sensible ✅

Hint: If weights sum to 1, the weighted mean is just Σ(w×x).
Common Mistakes: Forgetting to convert percentages to decimals or not ensuring weights sum to 1.
5. Values 10, 20, 30 have weights 2, 3, 5 respectively. Find the weighted standard deviation (round to 2 decimals).
medium
A. 7.55
B. 8.00
C. 7.81
D. 9.00

Solution

  1. Step 1: Compute weighted mean

    Σ(w×x) = (2×10)+(3×20)+(5×30)=20+60+150=230. Σw=2+3+5=10.
    Weighted mean μ = 230 ÷ 10 = 23.0.

  2. Step 2: Compute weighted squared deviations

    For 10: (10-23)² = 169 → weighted = 2×169 = 338.
    For 20: (20-23)² = 9 → weighted = 3×9 = 27.
    For 30: (30-23)² = 49 → weighted = 5×49 = 245.
    Σw×(x-μ)² = 338 + 27 + 245 = 610.

  3. Step 3: Weighted variance & SD

    Variance = 610 ÷ 10 = 61. SD = √61 ≈ 7.81.

  4. Final Answer:

    7.81 → Option C.

  5. Quick Check:

    Distribution spans 10-30; weighted mean 23 and SD ≈ 7.81 are consistent ✅

Hint: Do Σ(w×x) then Σ[w×(x-μ)²] ÷ Σw, then sqrt.
Common Mistakes: Using unweighted variance formula or dividing by number of unique values instead of Σw.

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